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3 years ago

How does knowing the slope and y-intercept help you graph and write the equation of a line?

Mathematics

1 answer:

IgorLugansk [536]3 years ago

8 0

Answer:

It allows to to know y-intercept formula which is used to graph a line.

Step-by-step explanation:

Y-intercept formula:

y=mx+b

M: slope (keep in fraction if it is fraction, to help you graph)

B: y-interecept

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You have $700 to invest in an account and need to have $950 in one year. What interest rate would you need to have in order to r

zhenek [66]

Answer:

136% = 1.36

Step-by-step explanation:

(950-700)/700

=0.3571 (0.36)

Then you have to plus one

0.36+1

=136% or 1.36

4 0

3 years ago

3x+-6+2 > = 5x -8......can someone please solve this

Maksim231197 [3]

Answer:

x ≤ 2

Step-by-step explanation:

If you referencing ">=" as greater than or equal to, follow the solution below:

Solve:

3x - 6 + 2 ≥ 5x - 8

Combine like terms.

3x - 4 ≥ 5x - 8

Subtract 5x from both sides.

-2x - 4 ≥ -8

Add 4 to both sides.

-2x ≥ -4

Divide both sides by -2, while flipping the inequality as well since you're dividing by a negative number.

x ≤ 2

Your answer would be x ≤ 2

6 0

3 years ago

(1) a) 5270 cl= ? dal

Ivanshal [37]

Answer:

Check below

Step-by-step explanation:

1) These metric volume units can be easily converted by dividing or multiplying by 10 and its multiple. Like this: each step up on the ladder multiply by 10. Each step down divide by 10

$a)5270 \:cl=527\:dl\\b)kl=5.3 \times 10=530 hl\\c)58000ml=5.8 dal =(\frac{58000}{10000})\\d)0.39 dal=3.9 l\\e)7.8 dal=780 dl\\f)57.2 ml=5.72 cl$ .

2) When it comes to area, the "ladder scheme" remains valid but now we'll multiply or divide by

$10^3$

Bear in mind these useful relations:

$1litre =\frac{1}{10^3}m^{3}$

$1 cm^{3} =1 ml$

$a) 3.7 l=3700 cm^{3}\\b)29.6 dm^{3}\\29.6 dm^{3} \rightarrow 29.6\times10^{3} cm^3=29.6\times10^{3} ml = 29.6\times10^{2} cl \:or\:2960 cl\\c)8.1l=8100 cm^{3}\\d)5l=\frac{5}{10^{-3}} m^{3}\\e)5.2 cl=52ml=52 cm^{3}=52\times10^{3}=52000 \:mm^{3}\\f)375 ml=375 cm^{3}\\g) 1300 cm^{3}=1300 ml=13 dl\\h) 8.6 ml= 8.6 cm^{3}\times\: 10^{3}=8600 mm^{3}\\i) 51.8\times 10^{11} l \rightarrow 51.8\times 10^{-11}km^{3}$