A regular polygon has ten (10) equal sides ( since it is regular).
We are given with the perimeter value which is 100 units and the perimeter formula is P = 10a
Solving for a (the side measurement), we have:
100 = 10a
a= 100/10
a =10
We can now proceed in solving the area and the formula is shown below:
Area = 5/2 a√ (5+2√5)
Area = 5/2 * 10√(5+2√5)
Area = 76.94 square units
The answer is 96.94 square units.
x = number of hours after 9 am (eg: x = 1 means 1 hr after 9 am, so 10 am)
f(x) = population count x hours after 9 am
f(1) = population count at 10 am (1 hour later)
f(2) = population count at 11 am (2 hrs after 9 am)
f(2) - f(1) represents the difference in population counts from 10 am to 11 am, or put another way, how much the population increased during that time interval.
Well if you use opposite operations then you will get
mg=6
to
g=6m
Answer:
1. 
2. ![(p^2-6)[1-q(p^2-6)]](https://tex.z-dn.net/?f=%28p%5E2-6%29%5B1-q%28p%5E2-6%29%5D)
Step-by-step explanation:
1. The first thing to do to factor the expression is to take the expression (a + 3) as a common factor with its lowest exponent.
Then the expression. 
remains as:
2. The first thing to do to factor the expression is to take the expression 
as its common factor with its lowest exponent.
Then the expression 
remains as:
![(p^2-6)[1-q (p^2-6)]](https://tex.z-dn.net/?f=%28p%5E2-6%29%5B1-q%20%28p%5E2-6%29%5D)
Answer:
The reuired probability is 0.756
Step-by-step explanation:
Let the number of trucks be 'N'
1) Trucks on interstate highway N'= 76% of N =0.76N
2) Truck on intra-state highway N''= 24% of N = 0.24N
i) Number of trucks flagged on intrastate highway = 3.4% of N'' = 
ii) Number of trucks flagged on interstate highway = 0.7% of N' = 
Part a)
The probability that the truck is an interstate truck and is not flagged for safety is 
where
is the probability that the truck chosen is on interstate
is the probability that the truck chosen on interstate is flagged
