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2 years ago

7. Susan has $21, and she has three times as much money as Diego. Write an equation for this

Mathematics

2 answers:

disa [49]2 years ago

8 0

Answer:

Diego has 7

Step-by-step explanation:

So if Susan has 21 and she has 3 times as much money as Diego the equation is 21 divided by 3. 21 divided by 3 is 3 groups of 7 so the answer is 7

Colt1911 [192]2 years ago

5 0

Answer:

Ok if Susan has $21 and She has 3 times as much money as Diego.

That means the equation is 21 divide by 3.

So that means Diego has $7.

Step-by-step explanation:

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Bad White [126]

Answer:

A. P - Q

Step-by-step explanation:

Q(x) = (x³ + 2x² + 3)(x² -2)

= x⁵ - 2x³ + 2x⁴ - 4x² + 3x² - 6

P - Q = (x⁵ - 2x³ + 2x⁴ - 4x² + 3x² - 6) - (x⁴ + 3x³ + 2x² - x + 2)

P - Q = x⁵ - x⁴ + 2x⁴ - 3x³ - 2x³ - 2x² - 4x² + 3x² + x - 2 - 6

P - Q = x⁵ + x⁴ - 5x³ - 3x² + x - 8

7 0

2 years ago

An expressions is shown. what is the value of the expression? 2315.5+(-3166.75)

Zepler [3.9K]

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2 years ago

The radius of a circle is 5 miles. What is the angle measure of an arc bounding a sector with area 10 square miles?

Lana71 [14]

10÷((22/7)×5^2))
=0.127

6 0

3 years ago

Express f(x) = |x-2| +|x+2| in the non-modulus form. Hence, sketch the graph of f.

alexgriva [62]

Recall that

$|x|=\begin{cases}x&\text{if }x\ge0\\-x&\text{if }x$

There are three cases to consider:

(1) When $x+2$ , we have $|x+2|=-(x+2)$ and $|x-2|=-(x-2)$ , so

$|x-2|+|x+2|=-(x-2)-(x+2)=-2x-4$

(2) When $x+2\ge0$ and $x-2$ , we get $|x+2|=x+2$ and $|x-2|=-(x-2)$ , so

$|x-2|+|x+2|=-(x-2)+(x+2)=4$

(3) When $x-2\ge0$ , we have $|x+2|=x+2$ and $|x-2|=x-2$ , so

$|x-2|+|x+2|=(x-2)+(x+2)=2x$

So

$|x-2|+|x+2|=\begin{cases}-2x-4&\text{if }x$

4 0

3 years ago

What is the area of this figure

konstantin123 [22]

Answer:

108

Step-by-step explanation:

add all of the numbers together and thats what you get :)

4 0

2 years ago