The product of two even numbers is even.
Let m and n be any integers so that 2m and 2k are two even numbers.
The product is 2m(2k) = 2(2mk), which is even.
Things to think about:
Why didn’t I just show you by using any two even numbers like the number 4 and the number 26?
Why did I change from "m" to "k" ? Are they really different numbers or could they be the same?
Why did I specifically say that m and k were integers?
The product of two odd numbers is an odd number.
Let m and k be any integers. This means that 2m+1 and 2k+1 are odd numbers.
The product is 4mk + 2m + 2k + 1 (hint: I used FOIL) which can be written as
2 ( 2mk + m + k ) + 1 which is an odd number.
Answer: m = 4
Step-by-step explanation: This is a linear equation.
Linear equations can be written in the form y = mx + b where
the multiplier, m, represents the slope of the line and the <em>b</em>
or the constant term represents the y-intercept of the line.
So the slope of this line is simply the multiplier
which is the coefficient of the x term which is 4.
The variable that's used to represent slope is <em>m</em>.
So we say that m = 4.
Given:
There are given that the zeroes and degrees of the polynomial:
Explanation:
From the concept of a polynomial:
A polynomial has a as zero if and only if (x -a) is a factor of the polynomial.
Then,
From the given polynomial:
Then,
Final answer:
Hence, the polynomial is shown below:
This intersection means that u have to find the same number in both sets
the answer is 3 , 7 , 13
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Answer:
-14
Step-by-step explanation:
Multiply the is together. Multiply the j's together. Add the answer. The answer is a scalar.
(7 × -2) + (5 × 0)
= -14
