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Katen [24]
3 years ago
10

Conversion question i cant find the right format online so

Chemistry
1 answer:
Delicious77 [7]3 years ago
5 0

Answer:

\frac{46 g}{1 mL} × \frac{1 kg}{1000 g}

= \frac{46 kg}{1000 mL}  

= \frac{46 kg}{1 L}

Explanation:

Since 1 kg is equal to 1000 g we multiply 46g/1mL by 1kg/1000g. Grams being on the bottom of the fraction so that they will cancel out. After this calculation we have 46kg/1000mL. This is equal to 46kg/1L, also written as 46kg/L.

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(Help!) What is the mass of hydrogen atoms that is measured at 72 u?​
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3 years ago
Based on the balanced chemical equation shown below, determine the mass percent of Fe3+ in a 0.6450 g sample of iron ore, if 22.
Genrish500 [490]

Answer:

38.9%

Explanation:

below, determine the mass percent of Fe3+ in a 0.6450 g sample of iron ore, if 22.40 mL of a 0.1000 M stannous chloride, SnCl2(aq), solution is required to completely react with the Fe3+ present in the ore sample. The chemical equation for the reaction is

2 Fe3+ (aq) + Sn2+ (aq) →2Fe2+ (aq) + Snº+(aq).

O 19.40%

O 6.196%

O 38.79%

O 9.697%

 2 Fe3+ (aq) + Sn2+ (aq) →2Fe2+ (aq) + Snº+(aq).ole of Sn2+

for every mole of Sn2+, tere are 2 moles of Fe3+

  1. 22.4/1000L of 0.1000 M Sn2+ = 22.4 X 0.10/1000 = 0.00224 mole

so there are 0.00224 X 2= 0.00448 moles Fe3+

iron atomic mass is 56

56 X 0.00448 = 0.251 gm Fe3+

so the mass % of the Fe3+ in the 0.645 gm iron ore sample is

(0.251/0.645) X 100 = 38.9%

8 0
3 years ago
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