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Serhud [2]
3 years ago
13

How many eight-digit numbers can be formed if the leading digit cannot be a zero and the last number

Mathematics
1 answer:
Korolek [52]3 years ago
8 0

Answer:

81 x 10^6

Step-by-step explanation:

x0000000

11111111x

22222222

33333333

....................

88888888

99999999

---------------------

The first digit and 8th digit column has only 9 numbers and the rest 6 column have 10 possible numbers

9 x 9 x 10^6 = 81 x 10^6

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