<h3><u>Correct Questions :- </u></h3>
Find the values of P for which the quadratic equation 4x²+px+3=0 , provided that roots are equal or discriminant is zero .
<h3><u>Solution</u>:- </h3>
Let us Consider a quadratic equation αx² + βx + c = 0, then nature of roots of quadratic equation depends upon Discriminant (D) of the quadratic equation.
For equal roots

So,

Here,
Now,







Thus, the values of P for which the quadratic equation 4x²+px+3=0 are-
4√3 and -4√3.
Answer:
5q + 5q + 5
2q + 5 + 8q
5(2q + 1)
Step-by-step explanation:
The bisector of an angle of a triangle divides the opposite side into segments that are proportional to the adjacent sides
VT/TK = VY/YK
95.2/168 = 34/YK
YK = (168·34)/95.2 = 60 cm
x = VY + YK = 34 + 60 = 94 cm
Answer:
x = 46, y = 67
Step-by-step explanation:
x = ∠ AEC = 46 ( alternate angles )
Since Δ ACE is isosceles then the base angles are congruent, then
y =
=
= 67
Answer:
Y=-5x-46.
Step-by-step explanation:
-5 is the slope, so Y=-5x+b. If you plug in (-8,-6), you get -6=40+b, so b has to be -46 for that to be true, I think.