You can resolve all of them.
so the first one would be 3q+2p
that second 2p+3q
the third 2p+2q+q which equals 2p+3q
they all end up as the same thing so both are equivalent
Okay try to round the whole number and see if you can solve that should help you
Is there a picture of the ramp?
Answer: the answer is 6
Step-by-step explanation:
Answer:
2sin(3θ) - √3 = 0
Step-by-step explanation:
sin(3θ) = √3/2
3θ = π/3 + 2kπ or 2π/3 + 2kπ, k = 0, ±1, ±2, ±3,...
θ = π/9 + 2kπ/3, 2π/9 + 2kπ/3
If k = 0, we get θ = π/9, 2π/9
If k = 1, we get θ = 7π/9, 8π/9
If k = 2, we get θ = 13π/9, 14π/9
Other values of k give values of θ lying outside of the interval [0, 2π).
