Answer:
<em>Answers below</em>
Step-by-step explanation:
<u>Equation</u>
Let's call:
p = number of pennies Janesa has in her pocket
n = number of nickels Janesa has in her pocket
She has 24 coins in total, thus:
![p + n=24\qquad\qquad [1]](https://tex.z-dn.net/?f=p%20%2B%20n%3D24%5Cqquad%5Cqquad%20%5B1%5D)
Since each penny is worth $0.01 and each nickel is worth $0.05, and Janesa has $1 in total:
Multiplying by 100:
![p+5n=100\qquad\qquad [2]](https://tex.z-dn.net/?f=p%2B5n%3D100%5Cqquad%5Cqquad%20%5B2%5D)
A. Completing the equation:
B.
From [1]:
Substituting into [2]:
Simplifying:
Rearranging:
B. There are 5 pennies in Janesa's pocket
C. Since each penny is worth $0.01, the total value of pennies is 5*$0.01=$0.05
The total value of the pennies is $0.05
D. The total value of the nickels is 19*$0.05 = $0.95
E. Jackson should say she has 19 nickels and 5 pennies
Carissa value after x months=current+amount deposited
louan value after x months=current-amount taken out
carissa depositied=amount per month times x months=80x
louan take out=amount per month tiems x months=60x
when wil amount be equal
se equal
cariss=lousa
250+80x=1230-60x
add 60x both sides
250+140x=1230
minus 250 both sides
140x=980
divide both sides by 140
x=7
find how much that is
250+80(7)=250+560=810
7 months both have $810
7x³ = 28x is our equation. We want its solutions.
When you have x and different powers, set the whole thing equal to zero.
7x³ = 28x
7x³ - 28x = 0
Now notice there's a common x in both terms. Let's factor it out.
x (7x² - 28) = 0
As 7 is a factor of 7 and 28, it too can be factored out.
x (7) (x² - 4) = 0
We can further factor x² - 4. We want a pair of numbers that multiply to 4 and whose sum is zero. The pairs are 1 and 4, 2 and 2. If we add 2 and -2 we get zero.
x (7) (x - 2) (x + 2) = 0
Now we use the Zero Product Property - if some product multiplies to zero, so do its pieces.
x = 0 -----> so x = 0
7 = 0 -----> no solution
x - 2 = 0 ----> so x = 2 after adding 2 to both sides
x + 2 = 0 ---> so = x - 2 after subtracting 2 to both sides
Thus the solutions are x = 0, x = 2, x = -2.
