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Tomtit [17]
3 years ago
13

What is 65 percent of 78?​

Mathematics
2 answers:
Allushta [10]3 years ago
5 0

Answer:

50.7

Step-by-step explanation:

siniylev [52]3 years ago
4 0
The percent of 65 of 78 is 50.7
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a plumber laying 500 meters of drain pipe required 20 men of working for 10 days . What length in meters would be laid by 50 men
belka [17]

Answer:

500 meters =20men =10days

To get the factor 500/(20*10)= 5/2 meters/day

For 50 men and 5days we don't know the meters

So we go by 50*(5/2)*5 =625meters

8 0
3 years ago
Need help its sector area
Paladinen [302]

Area of sector

=  \frac{30}{360}  \times  \pi \times  {(radius)}^{2}

=  \frac{30}{360}  \times  \ \frac{22}{7}  \times  {(12)}^{2}

=  \frac{30}{360}  \times  \ \frac{22}{7}  \times  12 \times 12

so the area = 37.71 square metre

8 0
2 years ago
You pay $10 to play the following game of chance. there is a bag containing 12 balls: three are red, five are green, and the res
Bogdan [553]

Answer:

$ -2.08  expected to lose  

Step-by-step explanation:

3 25.0%  $15.00   $5.00   $1.25  

5 41.7%  $10.00   $-     $-    

4 33.3%  $-     $(10.00)  $(3.33)  

     

    $(2.08)  expected to lose  

7 0
2 years ago
Lcm of 63, 80 and 102
photoshop1234 [79]

Answer:

85,680

Step-by-step explanation:

3 0
1 year ago
Can you help me with number 6? <br> Confused abit <br> Please
Sunny_sXe [5.5K]

You can see the three diagram attached. Each link is labeled with the probability: you have probability 1/6 that a six is rolled, and 5/6 that it is not rolled.


To answer the questions, find the path that brings you to the desired outcome, and multiply all the labels you meet.


First question:

To get three sixes, you have to choose the left path at each roll. The probability is always 1/6, so the answer is


\frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} = \frac{1}{6^3}


Second question:

To get no sixes, you have to choose the right path at each roll. The probability is always 5/6, so the answer is


\frac{5}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^3}{6^3}


Third question:

To get exactly one six, it can either be the first, second or third roll.


In all cases, you have to choose the left path once and the right path twice: left-right-right mean that you get the six in the first roll, right-left-right means that you get the six in the second roll, right-right-left means that you get the six in the third roll.


In every case, the left turn has probability 1/6, and the right turn has probability 5/6. The probability of each combination is thus


\frac{1}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^2}{6^3}


And since there are three of these combinations, The answer is


3\frac{5^2}{6^3}


Fourth question:

Since the question suggests to use what we already achieved, let's do it: having at least one six is the complementary event of having no sixes at all. If an event has probability p, its complementary has probability 1-p. So, since the probability of no sixes is known, the probability of at least one six is


1 - \frac{5^3}{6^3}

4 0
3 years ago
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