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4 years ago

What is 22/36 in lowest terms

Mathematics

2 answers:

Sergio039 [100]4 years ago

6 0

11/28 is the right answer.

daser333 [38]4 years ago

5 0

22/36 simplified is 11/18. I hope this helps. Tell me if you need an explanation! : )

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Max bought a pair of shorts on sale for 20% off the original price of $60 and another 25% off the discounted price. If sales tax

lawyer [7]

Answer = $39.78

100-20 =80

100-25=75

Multiply 60 x .80 to get $48

Then multiply 48 x .75 to get $36

Sales tax %10.5 = move decimal two places to left .105

Now multiply 36 x .105 =3.78

$3.78 equals your sales tax

Finally add $3.78+$36= $39.78

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3 years ago

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Stephanie, Mike, and Howard gather blackberries for their grandmother. Stephanie picks 438 pounds, Mike picks 2.5pounds, and How

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Answer:

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3 years ago

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If the bus is on time to the school 90% of the time, how many days can the school expect the bus on time out of 160 days?

andre [41]

Answer:

144 days

Step-by-step explanation:

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3 years ago

Factor 6a^2+7ax-3x^2

Gala2k [10]

6a² + 7ax - 3x²
6a² + 9ax - 2ax - 3x²
3a(2a) + 3a(3x) - x(2a) - x(3x)
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4 years ago

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From Euler’s relation eiθ = cosθ + isinθ,

adelina 88 [10]

Answer:

(a) The graphic representation is in the attached figure.

(b) $\cos(\theta) = \frac{e^{i\theta} + e^{-i\theta}}{2}$ .

(c) $\sin(\theta) = \frac{e^{i\theta} - e^{-i\theta}}{2i}$ .

Step-by-step explanation:

(a) Given a complex number $e^{i\theta}$ we know, from Euler's formula that $e^{i\theta} = \cos(\theta)+i\sin(\theta)$ . So, it is not difficult to notice that

$|e^{i\theta}|^2 = \cos^2(\theta)+\sin^2(\theta) =1$

so it is on the unit circumference. Also, notice that the Cartesian representation of the complex number is $(\cos(\theta), \sin(\theta))$ .

Now,

$e^{-i\theta} = \cos(\theta)+i\sin(-\theta) = \cos(\theta)-i\sin(\theta)$ .

Notice that $e^{-i\theta}$ has the same modulus that $e^{i\theta}$ , so it is on the unit circumference. Beside, its Cartesian representation is $(\cos(\theta), -\sin(\theta))$ .

So, the points $(\cos(\theta), \sin(\theta))$ and $(\cos(\theta), -\sin(\theta))$ are symmetric with respect to the X-axis. All this can be checked in the attached figure.

(b) Notice that

$e^{i\theta} + e^{-i\theta} = \cos(\theta)+i\sin(\theta) + \cos(\theta)-i\sin(\theta) = 2\cos(\theta)$

Then,

$\cos(\theta) = \frac{e^{i\theta} + e^{-i\theta}}{2}$ .

(c) Notice that

$e^{i\theta} - e^{-i\theta} = \cos(\theta)+i\sin(\theta) - \cos(\theta)+i\sin(\theta) = 2i\sin(\theta)$

Then,

$\sin(\theta) = \frac{e^{i\theta} - e^{-i\theta}}{2i}$ .

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3 years ago