The force the same object will exert if it accelerates at a rate of 7 m/s² is 35N
From the question,
We are to determine the force the object will exert.
From the information,
Newton’s Second Law of Motion states that the acceleration of an object is directly proportional to the force exerted on the object
Let acceleration be a
and
Force be F
Then we can write that,
F ∝ a
Then,
Introducing the constant, mass, m
We get
F = ma
Now, we will determine the mass of the object
F = 15 N
a = 3 m/s²
Putting the parameters into the formula, we get
15 = m × 3
∴ m = 15 ÷ 3
m = 5 kg
The mass of the object is 5 kg.
Now, to determine the force the same object will exert if it accelerates at a rate of 7 m/s²
That is,
a = 7 m/s²
and
m = 5 kg
Putting the parameters into the formula, we get
F = 5 × 7
F = 35 N
Hence, the force the same object will exert if it accelerates at a rate of 7 m/s² is 35N
Learn more here: brainly.com/question/13590154
\left(\mathrm{Decimal:\quad }x=-0.75\right)
hope it helps :P
Answer:
150
Step-by-step explanation:
one third of 2700 = 900
900/2 = 450
450/3 = 150
The answer to this is,1/4.
Supreme sold 29 tires. Set it up like this, with Supreme as your x and Prestige as y: 48x + 56y = 2008. This is an equation in terms of money, with x being the number of Supreme tires sold at $48 each and y being the number of Prestige tires sold at $56 each. We know that Prestige sold 11, so sub it for y and do the math: 48x = 2008 - 616; x = 29
