Use the correct notation to express the follow objects.

Please help me if you can. Please also write how you got the answer thank you.

babunello [35]

Answer:

Question 9: Variables: (smallest) s, q, r (largest)

Question 10: 5 whole numbers (7, 8, 9, 10, and 11)

Step-by-step explanation:

For question nine, there are two given statements... s=q-2 and q<r. Say we plug in 10000 (a really big #) in for q, then we would get s=9998 and r>10000. This way, we can see that s would be the smallest, then q, and r is the largest. <em>(q<r can be written as r>q)</em>

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For question 10, it states $\frac{1}{4}$ . This can be split into $\frac{3}{x}$ and $\frac{3}{x}$ . When x is 12 in the first equation then $\frac{3}{12} = \frac{1}{4}$ and when x is 6 in the second equation $\frac{3}{6} =0.5$ (0.5 is also $\frac{1}{2}$ ). Therefore, x must be a whole number less than 12 and greater than 6, and it cannot be either 12 or 6. Whole numbers between 6 and 12 are 7, 8, 9, 10, and 11 or 5 whole numbers.

4 0

2 years ago

Write the prime factorization of 138

Natali [406]

Answer:

138 ÷ 2 = 69

69 ÷ 2 = 34.5

69 ÷ 3 = 23

23 ÷ 3 = 7.67

23 ÷ 5 = 4.6

23 ÷ 7 = 3.2857

23 ÷ 11 = 2.0909

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23 ÷ 23 = 1

7 0

2 years ago

Dilate ABC below using A as the center and a<br> scale factor of 2. Leave all construction marks?

irina1246 [14]

<h3>Answer: Check out the diagram below.</h3>

Explanation:

Use your straightedge to extend segment AB into ray AB. This means you'll have it start at A and go on forever through B. Repeat these steps to turn segment AC into ray AC.

The two rays join at the vertex angle A. Point A is the center of the universe so to speak because it's the center of dilation. We consider it an invariant point that doesn't move. Everything else will move. In this case, everything will move twice as much compared to as before.

Use your compass to measure the width of AB. We don't need the actual number. We just need the compass to be as wide from A to B. Keep your compass at this width and move the non-pencil part to point B. Then mark a small arc along ray AB. What we've just done is constructed a congruent copy of segment AB. In other words, we've just double AB into AB'. This means the arc marking places point B' as the diagram indicates.

The same set of steps will have us construct point C' as well. AC doubles to AC'

Once we determine the locations of B' and C', we can then form triangle A'B'C' which is an enlarged copy of triangle ABC. Each side of the larger triangle has side lengths twice as long.

Note: Points A and A' occupy the same exact location. As mentioned earlier, point A doesn't move.