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2 years ago

I need help with this because this is hard

Mathematics

2 answers:

user100 [1]2 years ago

7 0

V equals 8 just had this test

SOVA2 [1]2 years ago

3 0

V=8, did it on equations solver

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According to a survey, 60 % of the residents of a city oppose a downtown casino. Of these 60 % about 8 out of 10 strongly opp

katrin [286]

Answer:

(a) 0.48

(b) 0.20

(c) it is not unusual for a radomly selected resident to oppose the casino and strongly oppose the casino.

Step-by-step explanation:

(a) Find the probability that a randomly selected resident opposes the casino and strongly opposes the casino.

The probability that a radomly selected resident opposes the casino and strongly opposes the cassino is the product of the two probabilities, that a resident opposes the casino and that it strongly opposes the casino (once it is in the first group) as it is shown below.

Use this notation:

Probability that a radomly selected resident opposes the casino: P(A)

Probability that a resident who opposes the casino strongly opposes it: P(B/A), because it is the probability of event B given the event A

i) Determine the probability that a radomly selected resident opposes the casino, P(A)

Probability = number of favorable outcomes / number of possible outcomes

P(A) is given as 60%, which in decimal form is 0.60

ii) Next, determine,the probability that a resident who opposes the casino strongly opposes it, P(B/A):

It is given as 8 out of 10 ⇒ P(B/A) = 8/10

iii) You want the probability of both events, which is the joint probability or intersection: P(A∩B).

So, you can use the definition of conditional probability:

P(B/A) = P(A∩B) / P(A)

iv) From which you can solve for P(A∩B)

P(A∩B) = P(B/A)×P(A) = (8/10)×(0.60) = 0.48

(b) Find the probability that a randomly selected resident who opposes the casino does not strongly oppose the casino.

In this case, you just want the complement of the probability that a radomly selected resident who opposes the casino does strongly oppose the casino, which is 1 - P(B/A) = 1 - 8/10 = 1 - 0.8 = 0.2.

(c) Would it be unusual for a randomly selected resident to oppose the casino and strongly oppose the casino?

You are being asked about the joint probability (PA∩B), which you found in the part (a) and it is 0.48.

That is almost 0.50 or half of the population, so you conclude it is not unusual for a radomly selected resident to oppose the casino and strongly oppose the casino.

8 0

3 years ago

How can you construct a Venn diagram comparing the numbers 1 through 100 in these 4 areas: odd, even, composite and prime?

Misha Larkins [42]

I am not sure but, give me a minute

6 0

3 years ago

Dr. Hall files 320 insurance claims every month.5% if those claims are rejected, how many claims are rejected? how many are acce

Drupady [299]

We are asked to find 5% od 320, because we know that 5% of 320 insurances are rejected.
5%=0.05
Now we can multiply 0.05 by 320
0.05*320=16 - its our result

8 0

3 years ago

!!!!!!! HELPPPPPP !!!!!! ASAP !!!!!!!!! HELPPPPPP!!!!!!!!!!!!

ElenaW [278]

Answer:

No you wouldn't because you are not dividing or multiplying by a negative number.

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Determine whether the statement is true or false. If it is true, explain why. If it is false, explain why or give an example tha

ioda

True.

You're allowed to move stuff around. Dogs of the AMS.

$y' = 3y - 2x + 6xy - 1 \\
y' = 3y + 6xy - 2x - 1 \\
dy/dx= 3y(1 + 2x) - (2x + 1) \\
dy/dx = 3y(1 + 2x) - (1 + 2x) \\
\frac{dy}{dx} = (3y - 1)(1 + 2x) \ \Rightarrow\ \dfrac{dy}{3y-1} = (1 + 2x) dx$

We wrote it in the form dy/dx = g(x) f(y) so this is separable.

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3 years ago