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4 years ago

How do you find the volume of a rectangular prism with a mixed fraction

2 answers:

8 0

First convert the mixed number into a improper fraction, then do length × width × hight. After covert your improper fraction back into a mixed number.

Pavel [41]4 years ago

3 0

<span>Same way you do when the sides are integers.

Example:
1 1/2 x 2 4/5 x 3 2/3

Step 1: First you turn the mixed numbers into improper fractions. (An easy way to do that is multiply the denominator by the whole number + the numerator.)

3/2 x 14/5 x 11/3

Step 2: Then you multiply the numerators.
3 x 14 x 11 = 462

Step 3: Then you multiply the denominators.
2 x 5 x 3 = 30

Step 4: Divide the numerator by the denominator
462/30 = 15 1/5

</span>

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The number of stamps in Kelly's stamp collection is 10 less than half the number of stamps in Marks collection. Let m represent

juin [17]

Answer:

The expression is $\frac{m}{2} -10=m$ .

Step-by-step explanation:

Given:

The number of stamps in Kelly's stamp collection is 10 less than half the number of stamps in Marks collection.

Let m represent the number of stamps in marks collection.

Now, to write an expression show the number of stamps in Kelly's collection.

Let $m$ represent the number of stamps in Marks collection.

And the number of stamps collection of Kellys be $\frac{m}{2} -10$

Now, to write an expression:

According to question:

$m=\frac{m}{2} -10$

$\frac{m}{2} -10=m$

Therefore, the expression is $\frac{m}{2} -10=m$ .

5 0

3 years ago

NOT A QUESTION

Paraphin [41]

Thank you, Mannster03. All of us on Brainly appreciate your help!

8 0

3 years ago

Read 2 more answers

1. Two object accumulated a charge of

In-s [12.5K]

Answer:

The magnitude of the electric force between these two objects

will be: 181.274 N.

i.e. F $=181.274$ N

Step-by-step explanation:

Two object accumulated a charge of 4.5 μC and another a charge of 2.8 μC.

q₁ = 4.5 μC = 4.5 × 10⁻⁶ C

q₂ = 2.8 μC = 2.8 × 10⁻⁶ C

separated distance = d = 2.5 cm

Calculating the magnitude of the force between two charged objects using the formula:

$F = \frac{1}{4\pi \epsilon_0}\frac{q_1 q_2}{r^2}$

$=\:\frac{4.5\times \:\:10^{-6}\:\times \:\:2.8\:\times \:\:10^{-6}}{4\:\times \:\left(3.14\right)\:\times \:\left(8.85\times \:10^{-12}\right)\times \left(2.5\times \:\:10^{-2}\right)^2}$

$=\frac{10^{-12}\times \:12.6}{10^{-12}\times \:4\times \:8.85\pi \left(10^{-2}\times \:2.5\right)^2}$ ∵ $4.5\times \:10^{-6}\times \:2.8\times \:10^{-6}=10^{-12}\times \:12.6$

$=\frac{10^{-12}\times \:12.6}{10^{-12}\times \:35.4\pi \left(10^{-2}\times \:2.5\right)^2}$ ∵ $\mathrm{Multiply\:the\:numbers:}\:4\times \:8.85=35.4$