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zhuklara [117]
2 years ago
13

The volume is 120.9 in. What is the missing dimension (X)

Mathematics
2 answers:
Elina [12.6K]2 years ago
5 0

Answer:

X = 2.5 in

Step-by-step explanation:

volume = L x W x H

120.9 = 9.3 x 5.2 x X

X = 2.5 in

andriy [413]2 years ago
3 0

Answer:

x=2.5 in approx

Step-by-step explanation:

volume of cuboid=L×B×H

120.9=9.3×x×5.2

x=120.9/(9.3×5.2)=2.48in

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Step-by-step explanation:

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\frac{a}{sinA}=\frac{b}{sinB}

Where:

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A=85.2°

B=71.6°

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b={sinB}*\frac{a}{sinA}\\b=\frac{sin(71.6)*13}{sin(85.2)}\\b=12

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Answer:

<em>The equation of the circle   (x +1) )² +(y-(2))² = (2(√5))²</em>

<em>   or </em>

<em>The equation of the circle    x² + 2 x + y² - 4 y  = 15</em>

<u>Step-by-step explanation:</u>

Given points end  Points are p(-3,-2) and q( 1,6)

<em>The distance of two points formula</em>

P Q = \sqrt{x_{2} - x_{1})^{2} + ((y_{2} -y_{1})^{2}   }

P Q = \sqrt{1 - (-3)^{2} + ((6 -(-2))^{2}   }

P Q = \sqrt{16+64} = \sqrt{80}

<em>The diameter 'd' = 2 r</em>

                       2 r = √80

                            = \sqrt{16 X 5}

                           = 4 \sqrt{5}

                     <em> r =  2√5</em>

<em>Mid-point of two end points </em>

<em>                        </em>(\frac{x_{1} + x_{2} }{2} , \frac{y_{1} +y_{2} }{2} ) = (\frac{-3+1}{2} ,\frac{-2 +6}{2} )<em></em>

<em>                                               = (-1 ,2)</em>

<em>Mid-point of two end points = center of the circle</em>

<em>                                     (h,k) = (-1 , 2)</em>

                 

The equation of the circle

           (x -h )² +(y-k)² = r²

<em>          (x -(-1) )² +(y-(2))² = (2(√5))²</em>

<em>         x² + 2 x + 1 + y² - 4 y + 4 = 20</em>

<em>          x² + 2 x + y² - 4 y  = 20 -5</em>

<em>           x² + 2 x + y² - 4 y  = 15</em>

<u><em>Final answer</em></u><em>:-</em>

<em>The equation of the circle   (x +1) )² +(y-(2))² = (2(√5))²</em>

<em>   or </em>

<em>The equation of the circle    x² + 2 x + y² - 4 y  = 15</em>

<em>                  </em>

6 0
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