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s344n2d4d5 [400]
3 years ago
8

A potter works 4 days a week, makes 15

Mathematics
2 answers:
nataly862011 [7]3 years ago
8 0
It is 3.75 for the answer



alekssr [168]3 years ago
5 0
So the answer would be 60 units?

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What does the point (2,24) represent?
almond37 [142]

Answer:

not sure what you mean here but..... 2 represents your x value which will go on the x intercept. And 24 represents your y value. When you have both of these values, you can plot it on a coordinate graph.


4 0
3 years ago
Ashlyn had some Barbie dolls. Joslyn has 78 barbies. Rounded to the nearest ten, together they have 140 Barbie dolls. How many d
azamat

ashlyn has 60 barbie dolls

6 0
3 years ago
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Escribe distintos repartos que se pondrían hacer de las cantidades siguientes asegúrate de hacer repartos equitativos y exactos
Keith_Richards [23]

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es 29.5?

Step-by-step explanation:

7 0
3 years ago
What is -3 - 9n= 42 I can’t be negative
maw [93]

If you were to correctly simplify this equation, the answer would be a negative.

The answer is: n = -5

Here's how I got my answer:

Step 1: Add 3 to both sides. Which leaves us with -9n=42+3

Step 2: Simplify 42+3 to 45. Which leaves us with -9n = 45

Step 3: Divide both sides by -9. Which leaves us with n = -45/9

Step 4: Simplify -45/9, to get your answer, n = -5.

4 0
3 years ago
What is the effect in the time required to solve a prob- lem when you double the size of the input from n to 2n, assuming that t
Inga [223]

Answer:

f(2n)-f(n)=log2

b.lg(lg2+lgn)-lglgn

c. f(2n)/f(n)=2

d.2nlg2+nlgn

e.f(2n)/(n)=4

f.f(2n)/f(n)=8

g. f(2n)/f(n)=2

Step-by-step explanation:

What is the effect in the time required to solve a prob- lem when you double the size of the input from n to 2n, assuming that the number of milliseconds the algorithm uses to solve the problem with input size n is each of these function? [Express your answer in the simplest form pos- sible, either as a ratio or a difference. Your answer may be a function of n or a constant.]

from a

f(n)=logn

f(2n)=lg(2n)

f(2n)-f(n)=log2n-logn

lo(2*n)=lg2+lgn-lgn

f(2n)-f(n)=lg2+lgn-lgn

f(2n)-f(n)=log2

2.f(n)=lglgn

F(2n)=lglg2n

f(2n)-f(n)=lglg2n-lglgn

lg2n=lg2+lgn

lg(lg2+lgn)-lglgn

3.f(n)=100n

f(2n)=100(2n)

f(2n)/f(n)=200n/100n

f(2n)/f(n)=2

the time will double

4.f(n)=nlgn

f(2n)=2nlg2n

f(2n)-f(n)=2nlg2n-nlgn

f(2n)-f(n)=2n(lg2+lgn)-nlgn

2nLg2+2nlgn-nlgn

2nlg2+nlgn

5.we shall look for the ratio

f(n)=n^2

f(2n)=2n^2

f(2n)/(n)=2n^2/n^2

f(2n)/(n)=4n^2/n^2

f(2n)/(n)=4

the time will be times 4 the initial tiote tat ratio are used because it will be easier to calculate and compare

6.n^3

f(n)=n^3

f(2n)=(2n)^3

f(2n)/f(n)=(2n)^3/n^3

f(2n)/f(n)=8

the ratio will be times 8 the initial

7.2n

f(n)=2n

f(2n)=2(2n)

f(2n)/f(n)=2(2n)/2n

f(2n)/f(n)=2

5 0
2 years ago
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