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2 years ago

What is 30 percent of 20 in fraction form

Mathematics

2 answers:

Rainbow [258]2 years ago

6 0

6/100 in fraction form. If simplified, it is 1/500.

soldier1979 [14.2K]2 years ago

4 0

It would be 6 as a whole number, 6/100 as a fraction

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trina is purchasing a new bike. the store is having a 20% off sale, and she has a 10% coupon. the original price of the bike is

Nina [5.8K]

We are given that:
i- The store is having 20% off sale
ii- Trina has a 10% coupon

Therefore, Trina will be having a discount = 20 + 10 = 30% of the bike's price
This means that:
Trina will pay 100% - 30% = 70% of the price

We are given that:
The original price of the bike = $89.75
We now know that:
Trina will pay 70% of its price

Therefore:
Final price = 70% * 89.75 = 0.7 * 89.75
Final price = $62.825

Hope this helps :)

8 0

3 years ago

Read 2 more answers

23.

Crazy boy [7]

Answer:

The number that cannot be the largest possible 6-digit number is;

(D) AAABCB

Step-by-step explanation:

From the question, we have;

A, B, and C = Distinct digits, therefore, A ≠ B ≠ C

The number of digits in the number to be formed = 6 digits

The number of 'A' in the number to be formed = 3

The number of 'B' in the number to be formed = 2

The number of 'C' in the number to be formed = 1

We have;

When A > B > C

The largest possible number = AAABBC

When C > A > B

The largest possible number = CAAABB

When B > A > C

The largest possible number = BBAAAC

When A > C > B

The largest possible number = AAACBB

Therefore, given that when A > B > C, the largest possible number = AAABBC, we have;

AAABBC > AAABCB, because B > C, therefore, within the tens and unit of the two 6 digit numbers, we have, BC > CB

∴ AAABBC > AAABCB and AAABCB, cannot be the largest possible 6-digit number

3 0

2 years ago

Help! Exponential Equation WITHOUT CALCULATOR

ale4655 [162]

$
1.
(2^{x} -2^{-x})^{2} = 4^{2} \\ \\2^{2x}-2*2^{x}*2^{-x} + 2^{-2x} =4^{2} \\ \\2^{2x}-2*2^{x-x} + 2^{-2x} =4^{2} \\ \\ 2^{2x}+ 2^{-2x} - 2=16 \\ \\ 2^{2x}+ 2^{-2x} = 18

\\ \\ 2.( 2^{x})^{3} - (2^{-x}^) ^{3}= (2^{x} -2^{-x})(2^{2x}+2^{x}*2^{-x}+2^{-2x})
\\ \\ ( 2^{x})^{3} - (2^{-x}^)^{3}=(2^{x} -2^{-x})(2^{2x}+2^{-2x}+2^{x}*2^{-x})
\\ \\ ( 2^{x})^{3} - (2^{-x}^)^{3}=(2^{x} -2^{-x})(2^{2x}+2^{-2x}+1)
\\ \\ ( 2^{x})^{3} - (2^{-x}^)^{3}=(2^{x} -2^{-x})((2^{2x}+2^{-2x})+1)
$

$\\ \\ ( 2^{x})^{3} - (2^{-x})^{3} =(4)((18)+1)= 76
\\ \\ 2^{3x}-2^{-3x} =76
$

4 0

3 years ago

Evaluate the expression 10b/a if b = 6 and a = 2

zimovet [89]

Answer:

Step-by-step explanation:

10b/a

b = 6

a =2

10(6)/2

10x6 / 2 = 60/2

= 30

8 0

2 years ago

Read 2 more answers

What is the sum of £4(0.5) "1? n=1 O S=1.5 OS = 2 O S = 4.5 O S= 8

Lelu [443]

B. 2 …………………………,.,,,,,.,.,.,.,.,,,.,

3 0

2 years ago