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vlabodo [156]
3 years ago
15

Determine the standard form of the equation for the circle with center (h,k) = (-5 ½) and radius r =1

Mathematics
1 answer:
wariber [46]3 years ago
8 0
Asuuing yo meant (h,k)=(-5,1/2)

equation is (x-h)^2+(y-k)^2=r^2
(h,k) is center and r=radious
given that (h,k)=(-5,1/2) and r=1
h=-5
k=1/2

(x-(-5))^2+(y- \frac{1}{2} )^2=1^2
(x+5)^2+(y- \frac{1}{2} )^2=1
if you wanted us to expand
x²+y^2+10x-y+25.25=1
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C

Step-by-step explanation:

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3 years ago
You are given the following information: Stockholders' equity = $323 million; price/earnings ratio = 14; shares outstanding = 8,
vagabundo [1.1K]

Answer:

$282.59 per share

Step-by-step explanation:

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3 0
3 years ago
Evaluate the function below for f(3)<br> f (x) = 3x2 - 5<br> what’s the answer
Novay_Z [31]
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4 0
3 years ago
What is the range of data in this box plot? what is the median?
jeka57 [31]
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------------------------------------------------------------------------------------------------------
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8 0
3 years ago
Read 2 more answers
What is the 2nd term when −3f3 + 9f + 6f4 − 2f2 is arranged in descending order?
Brilliant_brown [7]

For this case we have the following polynomial:

-3f ^ 3 + 9f + 6f ^ 4 - 2f ^ 2

To answer the question, what we must do is rewrite the polynomial in its standard form.

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Answer:

The second term of the polynomial is given by:

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6 0
3 years ago
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