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Evgesh-ka [11]
3 years ago
8

Can you please help me with this question​

Mathematics
1 answer:
harkovskaia [24]3 years ago
5 0

Answer:

(x,y) --> (x + 1, y - 4)

Step-by-step explanation

The figure is translated right 1 and down 4

(not completly sure but did not want to leave you hanging)

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Can someone help me pls!!!
Cerrena [4.2K]

Answer:

First one: Function

Second one: not a function (a function cannot have two outputs)

Third one: Function

Last one: Not a function (doesn't pass vertical line test)

Step-by-step explanation:

Hope it helps!

6 0
3 years ago
Read 2 more answers
Suppose that salaries for recent graduates of one university have a mean of $25,700 with a standard deviation of $1350. Using Ch
sergeinik [125]

Answer:

75% of the data will reside in the range 23000 to 28400.

Step-by-step explanation :

To find the range of values :

We need to find the values that deviate from the mean. Since we want at least 75% of the data to reside between the range therefore we have,

1 - \frac{1}{k^2} =\frac{75}{100}

Solving this, we would get k = 2 which shows the value one needs to find lies outside the range.

Range is given by : mean +/- (z score) × (value of a standard deviation)  

⇒ Range : 25700 +/- 2 × 1350

⇒ Range : (25700 - 2700) to (25700 + 2700)

Hence, 75% of the data will reside in the range 23000 to 28400.

3 0
3 years ago
Factorise x2-10x-24 plz help ​
Papessa [141]

Answer:

(х-4)(х-6)

Step-by-step explanation:

х¹= 4

х²=6

easy

7 0
3 years ago
Read 2 more answers
Use substitution method <br>3x +4y+175x-2y=11​
Viefleur [7K]

3x +4y+175x-2y=11

4y-2y+175x+3x=11

2y+178x=11

2y=11-178x

y=\frac{11-178x}{2}

y=-89x+\frac{11}{2}

178x=-2y+11

x=\frac{-2y+11}{178}

x=\frac{-1}{89} y+\frac{11}{178}

4 0
3 years ago
Use the approach in Gauss's Problem to find the following sums of arithmetic sequences.
Svet_ta [14]

The total value of the sequence is  mathematically given as

498501

<h3>The sum of the sequence is..?</h3>

Generally, the equation for Gauss's Problem is  mathematically given as

The sum of an arithmetic series;

1+2+3+...+n= n(n+1)/2

Given an arithmetic sequence,

1+2+3+...+998,

Here,

n = 998

1+2+3+...+n=n(n+1)/2

1+2+3+...+998=98(998 + 1)/2

998 x 999 1+2+3+...+998 =2

1+2+3+...+998 = 498501

In conclusion, 498501 is the total value of the sequence.

Read more about sequence

brainly.com/question/21961097

#SPJ1

6 0
2 years ago
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