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lara [203]
3 years ago
6

Find the equivalent expression by drawing a line from the left column to the right

Mathematics
1 answer:
Gala2k [10]3 years ago
6 0

Answer/Step-by-step explanation:

2(3x - 1) = 2*3x 2*-1 = 6x - 2

(x*y)2 = (xy)2 = 2xy

2(2x - 3) = 2*2x 2*-3 = 4x - 6

3x + 4x + 2 = (3x + 4x) + 2 = 7x + 2

7x - 7 = 7(x) - 7(1) = 7(x - 1)

x(6 + 9) = x(15) = 15x

2 + 9x + 1 + 3x = (9x + 3x) + (2 + 1) = 12x + 3

4(x + 2) + x = 4x + 8 + x = 4x + x + 8 = 5x + 8

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Solve 2 (x + 4) - 10 = 14 step by step
Blababa [14]

Answer:

x=8

Step-by-step explanation:

2(x+4) - 10 =14

distribute the 2       2x +8 -10 +14

simplify                     2x-2=14

add 2                        2x=16

devide by 2               x=8

3 0
3 years ago
Read 2 more answers
Helppp!! 21 - 3y = -18<br> 3x+ y = -5
Ugo [173]

Answer:

(-3,4)

Step-by-step explanation:

A system of equations is given to us. The given equations are ,

\implies 2x - 3y = -18

\implies 3x + y =-5

We need to plot the graph and find the solution of the given system . For that refer to attachment . The point at which both the lines of the graph will intersect each other will be the solution of the given system of equations .

From the graph we can see that it intersect at (-3,4) . Therefore the Solution is ,

\longrightarrow \underline{\underline{ Solution = (-3,4)}}

8 0
3 years ago
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If the probability of win is 0.2 and the probability of draw is 0.1 what's the probability of loss
Dovator [93]
The probability of loss is 

1 - 0.2 - 0.1 = 0.7
6 0
3 years ago
Pq=6x+25 and qr=16-3x; find pr
Viktor [21]

Given:\\\overline{PQ}=6x+25\\\overline{QR}=16-3x\\\\Finding:\overline{PR}

If \; Q \; is \; a \; point \; in \; between \; the \; line \; segment \; \overline{PR}, \; \\ then \; the \; distance \; of \; line \; segment \; \overline{PR} \; \\ can \; be \; found \; by \; adding \; line \; segment \; \overline{PQ} \; and \; \overline{QR}.

Using \; the \; concept \; \overline{PQ}+\overline{QR}=\overline{PR} \;,\\ we \; need \; to \; set \; up \; an \; equation \; given \; below:

\overline{PR} =6x+25 +16-3x\\\\Step \; 1: Grouping \; Like \; Terms\\\overline{PR} =6x-3x+25 +16\\\\Step \; 2: Combining \; Like \; Terms\\\overline{PR} =3x+41

Conclusion:

\overline{PR} \; is \; represented \; the \; expression \; 3x +41

3 0
3 years ago
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Find the indicated limit, if it exists.
jok3333 [9.3K]
For the limit to exist, the limits from either side must also exist and be identical. We have

\displaystyle\lim_{x\to2^-}f(x)=\lim_{x\to2}(x+3)=2+3=5

\displaystyle\lim_{x\to2^+}f(x)=\lim_{x\to2}(3-x)=3-2=1

Since the limits do not match, the overall limit does not exist.
6 0
3 years ago
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