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bekas [8.4K]
4 years ago
12

Rina Flipped a coin twenty times she flipped heads 4 times and tails 16 times what is the experimental probability that Rina wil

l flip heads in her next flip?
pls answer asap and pls explain but not to much THANK U
Mathematics
1 answer:
Triss [41]4 years ago
6 0

Answer: Assuming that all of the other variables when flipping the coin is constant. The experimental probability that Rina will flip heads in her next flip is 20%.

Step-by-step explanation:

Experimental Probability is the probability solely based on the results of the previous experiments done.

In this case the results of the previous experiments is 4 times landing on heads and 16 times landing on tails.

With this info, and with the question asking for the experimental probability of heads in her next flip, we can then set up a "proportion" using the number of times experimented (20 times; because 4 heads + 16 tails = 20 total times experimented) and the number of times it actually landed on heads in the past (4 times).

The proportion should be set up with the total number of times experimented the denominator and the number of times it landed on heads as the numerator.

So, the proportion should look like this,

4/20 = ___

evaluating the expression, in terms of percentage we get 20%

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Find the missing value of the sides.
umka2103 [35]

Answer:

The values for both of the missing sides is 8.

Step-by-step explanation:

The hypotenuse of a right triangle = a(square root of 2)

Therefore the other two missing sides equal a.

Therefore, the other two sides equal 8.

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3 years ago
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Six years from today you need $10,000. you plan to deposit $1,500 annually, with the first payment to be made a year from today,
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Like this variation of the problem! :)

We calculate the future value of the 6 annual deposits of $1500 at 8%:
F=1500(1.08^6-1)/(0.08)=11003.89
Since the last payment is due on the day of withdrawal, he would have paid $1500 to get back $11003.89, i.e. with an excess of 1003.89.
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3 years ago
-6n5x^3÷18nx^7<br>12m^8y^6÷-9my^4​
umka2103 [35]

Answer:

(-n^4 - 4 m^7 x^4 y^2)/(3 x^4)

Step-by-step explanation:

Simplify the following:

(-6 n^5 x^3)/(18 n x^7) + (12 m^8 y^6)/(-9 m y^4)

The gcd of -6 and 18 is 6, so (-6 n^5 x^3)/(18 n x^7) = ((6 (-1)) n^5 x^3)/((6×3) n x^7) = 6/6×(-n^5 x^3)/(3 n x^7) = (-n^5 x^3)/(3 n x^7):

(-1 n^5 x^3)/(3 n x^7) + (12 m^8 y^6)/(-9 m y^4)

Combine powers. (-n^5 x^3)/(3 n x^7) = (n^(5 - 1) x^(3 - 7) (-1))/3:

-(n^(5 - 1) x^(3 - 7))/3 + (12 m^8 y^6)/(-9 m y^4)

5 - 1 = 4:

-(n^4 x^(3 - 7))/3 + (12 m^8 y^6)/(-9 m y^4)

3 - 7 = -4:

-(n^4 x^(-4))/3 + (12 m^8 y^6)/(-9 m y^4)

The gcd of 12 and -9 is 3, so (12 m^8 y^6)/(-9 m y^4) = ((3×4) m^8 y^6)/((3 (-3)) m y^4) = 3/3×(4 m^8 y^6)/(-3 m y^4) = (4 m^8 y^6)/(-3 m y^4):

(4 m^8 y^6)/(-3 m y^4) - (n^4)/(3 x^4)

Combine powers. (4 m^8 y^6)/(-3 m y^4) = (4 m^(8 - 1) y^(6 - 4))/(3 (-1)):

-(n^4)/(3 x^4) + (4 m^(8 - 1) y^(6 - 4))/(-3)

8 - 1 = 7:

-(n^4)/(3 x^4) + (4 m^7 y^(6 - 4))/(-3)

6 - 4 = 2:

-(n^4)/(3 x^4) + (4 m^7 y^2)/(-3)

Multiply numerator and denominator of (4 m^7 y^2)/(-3) by -1:

-4/3 m^7 y^2 - (n^4)/(3 x^4)

Put each term in -(n^4)/(x^4×3) - (4 m^7 y^2)/3 over the common denominator 3 x^4: -(n^4)/(x^4×3) - (4 m^7 y^2)/3 = (-n^4)/(3 x^4) - (4 m^7 x^4 y^2)/(3 x^4):

-n^4/(3 x^4) - (4 m^7 x^4 y^2)/(3 x^4)

-n^4/(3 x^4) - (4 m^7 x^4 y^2)/(3 x^4) = (-n^4 - 4 m^7 x^4 y^2)/(3 x^4):

Answer: (-n^4 - 4 m^7 x^4 y^2)/(3 x^4)

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Answer:

8192

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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