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MrRa [10]
4 years ago
8

Rewrite the equation by completing the square. x^2−4x+3=0

Mathematics
1 answer:
harina [27]4 years ago
3 0

Answer:

x=1 or x=3

Step-by-step explanation:

Hello, please consider the following.

x^2-4x+3=0\\\\\text{Step 1 - complete the square}\\\\x^2-4x+3=x^2-2*2*x+3=(x-2)^2-4+3=(x-2)^2-1=0\\\\\text{Step 2 - move the constant to the right side, meaning adding 1 here.}\\\\(x-2)^2=1\\\\\text{Step 3 - take the root}\\\\x-2=\pm1\\\\x=2-1=1 \ \ or \ \ x=2+1=3

Thank you

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What values of x and y satisfy x + 2y = 6 and 2x + 3y = 4 simultaneously?
jeka94
First take x + 2y = 6 and isolate x:
x = 6 - 2y
Then substitute that for x in 2x + 3y = 4:
2(6 - 2y) + 3y = 4
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12 - y = 4
-y = -8
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Substitute y = 8 into x + 2y = 6 and 2x + 3y = 4:
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3 years ago
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Step-by-step explanation:

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