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3 years ago

Evaluate 5+(−3) = plz I need help

Mathematics

2 answers:

Illusion [34]3 years ago

7 0

Answer:

Step-by-step explanation:

it's just 5 - 3 lol, 5+-3=2

s344n2d4d5 [400]3 years ago

7 0

Answer:

Step-by-step explanation:

5+(-3)

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When you are adding a negative you are subtracting.

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In this equation, we can replace the "+(-)" with "-" like this:

--------------------------

5+(-3)=

5-3=

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With that, the final answer is...

5-3=

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What is the 7th term of the geometric sequence where a1 = -625 and a2 = 125

kykrilka [37]

Since the sequence is geometric, there is some constant $r$ such that the sequence is recursively given by

$a_n=ra_{n-1}$

By this definition, you can recursively substitute into the right hand side the definition for $a_{n-1},a_{n-2},\ldots$ to find an explicit formula for the $n$ th term.

$a_n=ra_{n-1}=r^2a_{n-2}=r^3a_{n-3}=\cdots=r^{n-1}a_1=-625r^{n-1}$

You know the second term, which means you can find $r$ :

$a_2=-625r^{2-1}\implies125=-625r\implies r=-\dfrac15$

So, the 7th term of the sequence is

$a_7=-625\left(-\dfrac15\right)^{7-1}=-\dfrac1{25}$

8 0

3 years ago

Please show me how to solve the problem

AlladinOne [14]

Answer:

(3x+1)

Step-by-step explanation:

So i start by the little 2 and then the 3 and then 19x +6

4 0

2 years ago

you rent an apartment that costs $1600 per month during the first year ,but the rent is set to go up 11.5% per year.what would b

RoseWind [281]

Answer:

$4,750.

Step-by-step explanation:

To determine the rental value of the apartment in the tenth year, knowing that it is worth 1,600 during the first year but that it will be adjusted annually to 11.5%, the following calculation must be made:

X = 1,600 x (1 + 0.115) ^ 10

X = 4,751.91

Thus, at ten years, rounded to the nearest tenth, the rental value will be $ 4,750.

7 0

3 years ago

Read 2 more answers

8. Is the following statement true or false? Justify your conclusion. If a and b are nonnegative real numbers and a + b =0, then

atroni [7]

Answer:

If $a + b = 0$ then $a = 0$ and $b =0$

a | b | a + b (answer)

0 | 0 | 0

0 | 1 | 1

0 | 2 | 2

1 | 0 | 1

2 | 0 | 2

1 | 1 | 2

2 | 1 | 3

Step-by-step explanation:

Considering the following conditions for the real numbers:

$a\geq 0\\b\geq 0$

Following the rules of these in-equations, it is possible to deduce:

$a + b \geq 0$

Then, if the proposed statement is:

$a + b = 0$

The conditions above shall comply the requirements established, but first, analyzing the statement:

If $a \geq 0$ and $b \geq 0$ then $a + b \geq a$ , $a + b \geq b$ and $a + b \geq 0$ .

If $a = 0$ and b a non negative real number, then $a + b \geq b$ , but because to $a = 0$ , then $a + b = b$ . Due to the commutative property of sums, the same behavior will be presented if $b = 0$ and a a non negative real number.