Question

Please help me solve this problem x and y

Answer 1

Answer:

$x=9,\\y=9\sqrt{3}$

Step-by-step explanation:

Using trig for right triangles:

$\sin 30^{\circ}=\frac{x}{18},\\x=18\sin 30^{\circ}=\boxed{9}$,

$\cos 30^{\circ}=\frac{y}{18},\\y=18\cos 30^{\circ}=18\cdot\frac{\sqrt{3}}{2}=\boxed{9\sqrt{3}}$.

If you aren't familiar with trig, this may have been introduced to you as a special triangle. In that case, the ratios of the sides of a 30-60-90 triangle are always:

$x:x\sqrt{3}:2x$, where $2x$ is the hypotenuse and $x$ is always the side opposite to the $30^{\circ}$ angle

Answer 2

Answer:

x=9    y=15.5885 or 15.6

Step-by-step explanation: