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3 years ago

Which equation has no solution?

Mathematics

1 answer:

Finger [1]3 years ago

4 0

Answer:

the third num equation has no solution i guess

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Identify the percent, amount, and base in this problem: 25% of what number is 40?

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a bag contains 8 red counters, 5 blue counters, and 3 green counters. what is the probability of not drawing a blue counter

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I will mark you brainiest if you can answer this <br> 12 - 13 x ≥38

Shtirlitz [24]

<h3><u>Explanation</u></h3>

Given Inequality

$12 - 13x \geqslant 38$

Solve the Inequality for x-term by making x as the subject.

Solving Inequality is almost the same as solving the equation.

$- 13x \geqslant 38 - 12 \\ - 13x \geqslant 26$

The problem is here. Some people might forget that when we move the negative coefficient to another side, we have to flip/swap or change the sign to opposite. That means we have to change from >= to <=

$x \leqslant \frac{26}{ - 13} \\ x \leqslant - 2$

Answer Check by substituting x = -2 in the Inequality.

$12 - 13( - 2) \geqslant 38 \\ 12 + 26 \geqslant 38 \\ 38 \geqslant 38$

The Inequality is true for x = -2 and that means it is also true when x is lesser than - 2.

Substitute x = -3

$12 - 13( - 3) \geqslant 38 \\ 12 + 39 \geqslant 38 \\ 51 \geqslant 38$

Notice that if we substitute the number that are lesser or equal to -2, the Inequality will be true.

<h3><u>Answer</u></h3>

<u> $\large \boxed{x \leqslant - 2}$ </u>

6 0

3 years ago

Anyone to help me answer this question am giving the brainliest

Arlecino [84]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

As we know,

$\boxed{\sin(a + b) = \sin(a) \cos(b) + \cos(a) \sin(b) }$

and

$\boxed{\sin(a - b) = \sin(a) \cos(b) - \cos(a \sin(b) ) }$

now, let's add them as shown ~

$\boxed{\sin(a + b) + \sin(a - b)}$

$\boxed{ \sin(a) \cos(b) + \cos(a) \sin(b) + \sin(a) \cos(b) - \cos(a) \sin(b) }$

$\boxed{2 \sin(a) \cos(b) }$

7 0

3 years ago