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3 years ago

Use the graph below to answer the question that follows:

Mathematics

1 answer:

Strike441 [17]3 years ago

3 0

By graphing the given points, we will get the attached figure
which represents:
f(x) = 3 sin x
but sin x = cos (x - π/2)
∴ f(x) = 3 cos ( x - π/2 )

The correct choice is option ⇒⇒⇒ <span>f(x) = 3 cos(x − pi over 2 ) </span>

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The average age of 15 students is 16 years. If teacher’s age is included the average increases

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because 15 +16 :31

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3 years ago

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kozerog [31]

2, 8, 32, 128,

Multiply by 4 for each number

8/2= 4

32/8= 4

128/32= 4

128*4=512

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4 years ago

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UkoKoshka [18]

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3 years ago

Use the mapping to determine which of the following are elements of the range.

Vadim26 [7]

Answer:

The elements of the range are the birthdays.

Step-by-step explanation:

A function is a distinct sort of relation in which each element of the domain is combined with precisely one element in the range. A mapping displays how the elements are combined.

A mapping figure comprises of two parallel columns. The 1st column signifies the domain of a function, and the other column for its range.

Lines or arrows are drawn from domain to range, to signify the relation between any two elements.

A function denoted by the mapping, in which each element of the range is combined with accurately one element of the domain is called one-to-one mapping.

From the diagram provided it is clear that the function denoted by the mapping is an one-to-one mapping.

The elements of the range are:

Birthday : {January 5 , January 7 , February 24 , March 1 , April 7 , May 30 , July 20 , August 1 , November 13 , November 26 }

Thus, the elements of the range are the birthdays.

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4 years ago

If the graph of the function f has a multiple zero at x = 2, what is a possible exponent of the factor x - 2? Justify your reaso

melomori [17]

Answer:

$(x-2)^2$

The exponent is 2.

Step-by-step explanation:

Remember multiplicity rules:

If a factor has an odd multiplicity (e.g. it is raised to 1, 3, 5...) then it will cross the x-axis.
If a factor has an even multiplicity (e.g. it is raised to 2, 4, 6...) then it will bounce off the x-axis.

At x=2, we have the factor (x-2).

From the graph, we can see that the graph bounces off at that point.

Hence, the multiplicity of (x-2) must be even.

Therefore, a possible exponent for the factor (x-2) is 2. Any even number will suffice.

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3 years ago