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blagie [28]
3 years ago
12

Adiciona el término que hace falta para que sea un trinomio cuadrado perfecto x^2+3x+1​

Mathematics
1 answer:
adell [148]3 years ago
3 0

Answer:

COSAS

Step-by-step explanation:

en realidad hablo inglés XD

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Write the number that has one unit 3 hundreds 8 thousands and 6 tens of thousands
ValentinkaMS [17]

Answer:

i believe it's   .0386

Step-by-step explanation:

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4 years ago
X varies directly with<br> y. If x = 60 when<br> y = 75. find x when<br> y = 32.
Alex Ar [27]

Answer:

x=17

Step-by-step explanation:

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PLEASE HELP!!! I WILL GIVE BRAINY!!!
11111nata11111 [884]
The first one is 4/3

We can solve by,

{x}^{2} \times 180 = 320

x = \frac{4}{3}

{ \frac{4}{3} }^{2} \times 180 = 320 = true

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The second one is 35.

Idk how to explain...

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The third one is a 6 - gon therefore cannot be C or D.

I'd say the third one is A., it looks like it's caving in.
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2 years ago
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Consider the function f given by f(x)=x*(e^(-x^2)) for all real numbers x.
NISA [10]

Answer:

\frac{\sqrt{\pi}}{4}

Step-by-step explanation:

You are going to integrate the following function:

g(x)=x*f(x)=x*xe^{-x^2}=x^2e^{-x^2}  (1)

furthermore, you know that:

\int_0^{\infty}e^{-x^2}=\frac{\sqrt{\pi}}{2}

lets call to this integral, the integral Io.

for a general form of I you have In:

I_n=\int_0^{\infty}x^ne^{-ax^2}dx

furthermore you use the fact that:

I_n=-\frac{\partial I_{n-2}}{\partial a}

by using this last expression in an iterative way you obtain the following:

\int_0^{\infty}x^{2s}e^{-ax^2}dx=\frac{(2s-1)!!}{2^{s+1}a^s}\sqrt{\frac{\pi}{a}} (2)

with n=2s a even number

for s=1 you have n=2, that is, the function g(x). By using the equation (2) (with a = 1) you finally obtain:

\int_0^{\infty}x^2e^{-x^2}dx=\frac{(2(1)-1)!}{2^{1+1}(1^1)}\sqrt{\pi}=\frac{\sqrt{\pi}}{4}

5 0
3 years ago
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Please help me, I have minimum time
natita [175]
X= 5x Y=-6 I just added them together
8 0
2 years ago
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