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Tanya [424]
2 years ago
8

Amira wants to ride her bicycle 48 miles this week. She has already ridden 18 miles. If she rides for 5 more days, write and sol

ve an equation which can be used to determine xx, the average number of miles she would have to ride each day to meet her goal.
Mathematics
1 answer:
sergij07 [2.7K]2 years ago
5 0
Answer is 6 miles per day
Answer is equation 48 = (x)(5) + 18

Step by step

You can use y intercept equation
y = mx + b

y = 48 total miles
m = rate of miles unknown
x = 5 days
b = starting point of 18 miles already ridden

48 = (x) (5) + 18

48 = 5x + 18

Subtract 18 from both sides to isolate the variable

48 - 18 = 5x + 18 - 18

30 = 5x

Now divide both sides by 5 to solve for x

30/5 = 5/5 x

X = 6 miles per day

Check your work, substitute 6 for x in your equation

48 = (6) (5) + 18
48 = 30 + 18
48 = 48

Problem solved!!
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468 divided by 4 which is 117
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Highlight and name a pair of overlapping congruent triangles in each diagram. State whether the triangles are congruent by SSS,
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Answer:

1. ONA and OMP, AAS

2. MRQ and SRQ, SSS

3. ARF and ROA, HL

4. GOS and GRT, AAS

6 0
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Read 2 more answers
Given: X = r + 2, Y = 2r - 9, and Z = r 2 + 17r + 30. Simplify [X · Y - Z] ÷ X.
ale4655 [162]
( (r+2) * (2r-9)-(r^2+17r+30) )/(r+2)

none of the parenthetical operations or power operations can be simplified further, so multiplication and division first, left to right:

(2r(r+2) -9(r+2) - r^2 + 17r +30)/(r+2)

(2r^2 + 2r -9r+18 -r^2 +17r +30 )/(r+2)

(r^2 +10r +48)/(r+2)


7 0
3 years ago
Please help me i need to complete this by tomorrow
lisov135 [29]

Answer:

Step-by-step explanation: Need to work out your scale factor which is 1.5.

8 * 1.5 = 12

CE = 12

12 * 9 = 108/2 = 59 that is the area of triangle ACE

8 * 6 = 48/2 = 24 that is the area of triangle BCD

ACE - BCD = ABDE

59 - 24 = 35cm^2

8 0
2 years ago
Find the measure of the indicated angle. Round to the nearest degree.
slava [35]

Answer:

Step-by-step explanation:

Use SOH CAH TOA to recall how the trig functions fit on a triangle

SOH: Sin(Ф)= Opp / Hyp

CAH: Cos(Ф)= Adj / Hyp

TOA: Tan(Ф) = Opp / Adj

5)

Adj = 14

Hyp = 26

∠X

so use

CAH

Cos(X) = 14/26

X = arcCos(14/26)

X = 57.421°

X = 57.4 ° ( rounded to nearest 10th )

6)

∠X

Hyp = 46

Opp = 12

use SOH

Sin(x) = 12/46

X = arcSin(12/46)

X = 15.121°

X = 15.1 ° ( rounded to nearest 10th )

7)

∠X

Adj = 29

Opp = 24

use TOA

Tan(x) = 29 / 24

X = arcTan( 29 /24)

X = 50.389

X = 50.4 °  ( rounded to nearest 10th )

8)

∠X

Adj = 22

Opp = 6

use TOA agian

Tan(x) = 6 / 22

X = arcTan(6/22)

X = 5.194

X = 5.2 °  ( rounded to the nearest 10th )

:)

8 0
3 years ago
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