The equation that represents the linear function for the set of ordered pairs is: A. y = -3x + 2.
<h3>What is the Equation of a Linear Function?</h3>
Equation of a linear function, where m is the slope and b is the y-intercept, is expressed as y = mx + b.
Find the slope (m):
Slope (m) = change in y/change in x = (-7 -(-4)) / (3 - 2)
Slope (m) = -3/1 = -3
Find b by substituting m = -3 and (1, -1) = (x, y) into y = mx + b:
-1 = -3(1) + b
-1 = -3 + b
-1 + 3 = b
2 = b
b = 2
Substitute m = -3 and b = 2 into y = mx + b
y = -3(x) + 2
y = -3x + 2
Therefore, the equation that represents the linear function for the set of ordered pairs is: A. y = -3x + 2.
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Answer:
The height of cone is decreasing at a rate of 0.085131 inch per second.
Step-by-step explanation:
We are given the following information in the question:
The radius of a cone is decreasing at a constant rate.

The volume is decreasing at a constant rate.

Instant radius = 99 inch
Instant Volume = 525 cubic inches
We have to find the rate of change of height with respect to time.
Volume of cone =

Instant volume =

Differentiating with respect to t,

Putting all the values, we get,

Thus, the height of cone is decreasing at a rate of 0.085131 inch per second.
Answer:
I think it is 174
Step-by-step explanation:
Answer:
false a = -3
Step-by-step explanation:
7v^2 + 2v^3 -7v - (5v^3 -4v^2 +10v)
7v^2 + 2v^3 -7v - 5v^3 +4v^2 -10v
-3v^3 + 11v^2 -17v