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Liono4ka [1.6K]
3 years ago
7

Which line shows the first error in the solution?

Mathematics
1 answer:
Andrew [12]3 years ago
4 0
The part of the solution that is incorrect is (5). This is because -10 -8 = -18. :)
You might be interested in
Write an equation of the line that passes through (-1,7) and is perpendicular to the line y=-1/8x -1
kirill115 [55]

Answer:

y = 8x + 15

Step-by-step explanation:

Step 1: Find slope of perpendicular line

<em>Take the negative reciprocal of the 1st equation</em>

m = 8

y = 8x + b

Step 2: Find <em>b</em>

7 = 8(-1) + b

7 = -8 + b

b = 15

Step 3: Rewrite perpendicular equation

y = 8x + 15

8 0
3 years ago
What is the answer to this problem? Try to describe as much as you can.
Zinaida [17]

Answer:

On the grid

Step-by-step explanation:

Go 226 spaces to the left of the x axis, when you get there go 216 up on the y axis

8 0
3 years ago
Two researchers conducted a study in which two groups of students were asked to answer 42 trivia questions from a board game. Th
Verizon [17]

Answer:

(21.9-19.8) -1.966\sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 1.422

(21.9-19.8) -1.966 \sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 2.778

And we are 95% confident that the true difference means are between 1.422 \leq \mu_1 -\mu_2 \leq 2.778

Step-by-step explanation:

We know the following info:

\bar X_1 = 21.9 sample mean for group 1

\bar X_2 = 19.8 sample mean for group 2

s_1 = 3.4 sample standard deviation for group 1

s_2 = 3.5 sample standard deviation for group 2

n_1 = 200 sample size group 1

n_2 = 200 sample size group 2

We want to find a confidence interval for the difference of means and the correct formula to do this is:

(\bar X_1 -\bar X_2) \pm t_{\alpha/2} \sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}

Now we just need to find the critical value. The confidence level is 0.95 then the significance is 1-0.95 =0.05 and \alpha/2 =0.025. The degrees of freedom are given by:

df= n_1 +n_2 -2= 200+200-2= 398

The critical value for this case would be :t_{\alpha/2}=1.966  

And replacing into the confidence interval formula we got:

(21.9-19.8) -1.966\sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 1.422

(21.9-19.8) -1.966 \sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 2.778

And we are 95% confident that the true difference means are between 1.422 \leq \mu_1 -\mu_2 \leq 2.778

5 0
3 years ago
17. The area of a rectangular sandbox is 8x2 + 18x + 9. If one of it's dimensions is (2x + 3), what is the other
Natasha2012 [34]

Answer:

The other dimension of the sandbox must be (4x+3).

Hope this helps! Have a good day!

6 0
3 years ago
What's 4.88 rounded to the nearest tenth......
Ugo [173]
The first decimal point is tenth. 4.88
when rounding, we just look at the number right after the number you want to round to. it's 8 right? since 8 is closer to 10 than 0,
we round it to 4.9
                  (4.8 + 0.10)
5 0
3 years ago
Read 2 more answers
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