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Liono4ka [1.6K]
3 years ago
7

Which line shows the first error in the solution?

Mathematics
1 answer:
Andrew [12]3 years ago
4 0
The part of the solution that is incorrect is (5). This is because -10 -8 = -18. :)
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If K is the midpoint of JL, JK = 9x -1 and KL = 2x +27, find JL
Liula [17]

Answer:

JL = 70

Step-by-step explanation:

Since K is the midpoint of JL then JK = KL and

JL = JK + KL = 9x - 1 + 2x + 27 = 11x + 26

solve for x using JK = KL

9x - 1 = 2x + 27 ( subtract 2x from both sides )

7x - 1 = 27 ( add 1 to both sides )

7x = 28 ( divide both sides by 7 )

x = 4, hence

JL = 11x + 26 = (11 × 4 ) + 26 = 44 + 26 = 70


3 0
3 years ago
Read 2 more answers
Find the amount of interest on $1,500 invested for 20 days at 6.75%, compounded daily. $_____
LekaFEV [45]

Answer:

The required amount of interest is $5538.  

Step-by-step explanation:

Given : $1,500 invested for 20 days at 6.75%, compounded daily.

To find : The amount of interest ?

Solution :

Applying compound interest formula,

A=P(1+r)^t

Where, A is the amount

P is the principal P=$1500

r is the interest rate  r=6.75%=0.0675 compounded daily

t is the time t=20 days

Substitute the value in the formula,

A=P(1+r)^t

A=1500(1+0.0675)^{20}

A=1500(1.0675)^{20}

A=1500\times 3.69

A=\$5538

Therefore, The required amount of interest is $5538.

4 0
4 years ago
What is the quotient of (x^3+7x^2+7x-6) ÷ (x-2)?
valina [46]

x^2 +9x +25 + 44/x-2

Step-by-step explanation:


3 0
3 years ago
July 15: Hire part-time helper to be paid $12 per hour. Pay periods are the 1st through the 15th and 16th through the end of the
nikklg [1K]

Answer:

The information above is just a part of a long question.The main question is  found in the attached as well as the answer following a step by step methodical approach.

Step-by-step explanation:

Take a good at the full question before venturing into the statements prepared so as to have a thorough understanding of the requirements and how the answers provided have touched upon the requirements.

Download xlsx
3 0
3 years ago
Completely factor each of the given polynomials. If a polynomial cannot be factored, write "not factorable."
Art [367]
4x^2+23x+15=0
Δ=23^2-4*4*15=529-240=289

x1= (-23+17)/8=-6/8= -3/4
x2= (-23-17)/8=-5

4x^2+23x+15= 4(x+3/4)(x+5)=(4x+3)(x+5)
6 0
3 years ago
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