Answer:
DUE= {0,10,12,18,19}
Step-by-step explanation:
The union of two sets is a set which contains all the elements of both the sets. thus DUE= {0,10,12,18,19}
Answer:
The system of equations has a one unique solution
Step-by-step explanation:
To quickly determine the number of solutions of a linear system of equations, we need to express each of the equations in slope-intercept form, so we can compare their slopes, and decide:
1) if they intersect at a unique point (when the slopes are different) thus giving a one solution, or
2) if the slopes have the exact same value giving parallel lines (with no intersections, and the y-intercept is different so there is no solution), or
3) if there is an infinite number of solutions (both lines are exactly the same, that is same slope and same y-intercept)
So we write them in slope -intercept form:
First equation:

second equation:

So we see that their slopes are different (for the first one slope = -6, and for the second one slope= -3/2) and then the lines must intercept in a one unique point. Therefore the system of equations has a one unique solution.
Answer:
<em>The new mixture is 49% peanuts.</em>
Step-by-step explanation:
The first batch of 9 lb of mixed nuts contains 55% peanuts. This means the quantity of peanut is:
9*55/100=4.95 lb
The second batch of 6 lb of mixed nuts contains 40% peanuts. This means the quantity of peanut is:
6*40/100=2.4 lb
The total quantity of peanut in the mix is
4.95 lb + 2.4 lb =7.35 lb
There are 9 lb + 6 lb = 15 lb of mix. Thus, the percent of peanut in the mix is:
7.35 / 15 * 100 = 49%
The new mixture is 49% peanuts.
5x-9y=-65
10x-3y=20
Multiple the first equation by 2
10x-18y=-130
10x -3y=20
Then subtract the two equations to get rid of the x
21y=-150
Divide the -150 by 21
Y=-7.14
Plug the y into the original equation. (Either one)
5x-9(-7.14)=-65
5x-64.28=-65
Then add 64.28 to the -65
5x=-0.72
Divide by 5
X=-0.144
I hope this is right
Step-by-step explanation:
a. the domain ={-3, 0, 1, 2}
the range = {6, 2, 0, -3}
the relation is a function
b. the domain = {-1, 2, 1}
the range = { -4, 8, 4}
the relation is not a function