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lora16 [44]
3 years ago
7

What is the central idea of the role of myths

Advanced Placement (AP)
1 answer:
Delvig [45]3 years ago
3 0

Answer:

One answer is that it leans on the message impossible is not impossible and indicates precise reasoning for general things ie) one myth to many others in maths some people would say maths it is not creative; but I guess it has a key magic factor over time for those who both study or have basic skills from and through at least problem solving.

Such myth can be reversed for those who find the study of maths interesting.

As the basics for some people do not find it challenging enough just repetitive and wouldn't understand what context of creativity.

As extract shows below.

Explanation:

Creativity is as central to mathematics as it is to art, literature, and music. The act of creation involves diametrical opposites--working intensely and relaxing, the frustration of failure and elation of discovery, satisfaction of seeing all the pieces fit together. It requires imagination, intellect, intuition, and aesthetic about the rightness of thing

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Psychology A cumulative exam answer????
tino4ka555 [31]

Answer:

Cumulative is formed by the addition of new material of the same kind. Comprehensive is covering completely or broadly.

Explanation:

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3 years ago
1a)Briefly explain ONE major difference between Josephson and Gutman's historical interpretation of the effects of industrializa
kicyunya [14]

Answer:

Josephson believed that industrialization created economic inequalities among people. Gutman, on the other hand, believes that industrialization has caused harmful tension among immigrants and natives.

Explanation:

For Josephson, industrialization created an immense social inequality between rich and poor, where the rich enriched themselves through the exploitation of workers and illegal activities that made them increasingly powerful, while the working class was increasingly exploited.

Gutman, on the other hand, believed that industrialization attracted many immigrants who were trying to get a job in the factories and thereby established competition with American citizens. Such competition generated social tension in the working class, which was often harmful.

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3 years ago
1. The rate at which people enter a movie theater on a given day is modeled by the function S defined by S(t) = 80 -12 cos 6 The
Arlecino [84]

Hi there!

a.

To find the total amount of people that have ENTERED by t = 20, we must take the integral of the appropriate function.

\text{Amount that entered} = \int\limits^{20}_{10} {S(t)} \, dt \\\\ = \int\limits^{20}_{10} {80 - 12cos(\frac{t}{5})} \, dt

Evaluate using a calculator:

= 899.97 \approx \boxed{900\text{ people}}

b.

To solve, we can find the total amount of people that have entered of the interval and subtract the total amount of people that have left from this value.

In other terms:
\text{Amount of people} = \int\limits^{20}_{10} {S(t)} \, dt - \int\limits^{20}_{10} {R(t)} \, dt

We can evaluate using a calculator (math-9 on T1-84):


\text{\# of people} = \int\limits^{20}_{10} {80-12cos(\frac{t}{5})} \, dt - \int\limits^{20}_{10} {12e^{\frac{t}{10}}+20} \, dt

= 899.97 - 760.49 = 139.47 \approx \boxed{139 \text{ people}}

c.

If:
P(t) = \int\limits^t_{10} {S(t) - R(t)} \, dt

Then:

\frac{dP}{dt}  = P'(t)= \frac{d}{dt}\int\limits^t_{10} {S(t) - R(t)} \, dt  = S(t) - R(t)

Evaluate at t = 20:


S(20) = 80 - 12cos(\frac{20}{5}) = 87.844\\\\R(20) = 12e^{\frac{20}{10}} + 20 = 108.669

S(20) - R(20) = 87.844 - 108.669 = -20.823

This means that at t = 20, there is a <u>NET DECREASE</u> of people at the movie theater of around 20.823 (21) people per hour.

d.

To find the maximum, we must use the first-derivative test.

Set S(t) - R(t) equal to 0:

80 - 12cos(\frac{t}{5}) - 12e^{\frac{t}{10}} - 20 = 0\\\\60 - 12(cos(\frac{t}{5}) + e^{\frac{t}{10}})= 0

Graph the function with a graphing calculator and set the function equal to y = 0:

According to the graph, the graph of the first derivative changes from POSITIVE to NEGATIVE at t ≈ 17.78 hours, so there is a MAXIMUM at this value.

<u>Thus, at t = 17.78 hours, the amount of people at the movie theater is a MAXIMUM.</u>

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