Answer:
Step-by-step explanation:
Let a , b , c & d be the no. of chairs in hall A , B , C & D respectively.
Given,
b = 4a
c = a + 15
d = a + 8 + 4a = 5a + 8
Now,
Total no. of chairs (T) = a + b + c + d
= a + 4a + a + 15 + 5a + 8
= 11a + 23
Now,
Average chairs in each hall (Avg) = T/4
= (11a + 23)/4
Answer:
is this a joke? xd. 2+2=4.
The answer is -8/15. This is a for sure correct answer.
Answer:
This is the answer: choose
A
D
E
Because the tell if he number is big or small
