Andrew can buy maximum 3 meals this weekend.
From given question,
Andrew must spend less than 53$ on meals during the weekend.
He has already spent 21$ on meals costing 8$ average.
Let x, the number of meals
So, we get an inequality,
8x + 21 < 53
We need to find the number of meals he can buy this weekend.
From above inequality,
⇒ 8x + 21 < 53
⇒ 8x < 53 - 21
⇒ 8x < 32
⇒ x < 4
This means, from 1 to 3 meals.
Therefore, Andrew can buy maximum 3 meals this weekend.
Learn more about an inequality here:
brainly.com/question/19003099
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Answer:
y= 25x
Step-by-step explanation:
Hello! And thank you for your question!
Use Pemdas to get
3^(n+2)*4=3^28
Rewrite the equation:
3^4(n+2) = 3^28
Cancel the base of 3:
4(n + 2) = 28
Then divide 4 on both sides:
2 + n = 28/4
Simplify 28/4:
2 + n = 7
Subtract 2 on both sides:
n = 7 - 2
Finally simplify 7 - 2:
n = 5
Final Answer:
n = 5
A(5) = 2 + 5^2 = 2 + 25 = 27
Step-by-step explanation:
This sequence is defined as a(n) = 2 + n^2.
Thus, a(1) = 2 + 1^2 = 2 + 1 = 3
Then a(5) = 2 + 5^2 = 2 + 25 = 27
Answer:
36
Step-by-step explanation:
Use pythagorean theorem
side 1 = 9
side 2 = 12
9^2 + 12^2 = third side ^2
third side = 15
9+12+15 = 36
Hope this helpful!!!!! :)
