Answer:
I think jillian will have to run 10 miles
Step-by-step explanation:
2 miles = 100 calories
in order to burn 500 calories
2 miles = 100 calories burned
4 miles = 200 calories burned
6 miles = 300 calories burned
8 miles = 400 calories burned
10 miles = 500 calories burned
Answer:
The value of T₂₀ - T₁₅ is <u>-20</u>.
Step-by-step explanation:
<u>Given</u> :
<u>To</u><u> </u><u>Find</u> :
<u>Using Formula</u> :
General term of an A.P.

- >> Tₙ = nᵗʰ term
- >> a = first term
- >> n = no. of terms
- >> d = common difference
<u>Solution</u> :
Firstly finding the A.P of T₂₀ by substituting the values in the formula :






Hence, the value of T₂₀ is a + 19d.

Secondly, finding the A.P of T₁₅ by substituting the values in the formula :






Hence, the value of T₁₅ is a + 14d

Now, finding the difference between T₂₀ - T₁₅ :









Hence, the value of T₂₀ - T₁₅ is -20.

Answer:
52°
Step-by-step explanation:
In the figure attached, Circle A is shown. There we can see that:
∠BC + ∠CD = ∠BAD
We know that Arc BC measures 96° and arc BAD measures 148°. Replacing this data into the equation and solving for Arc CD, we get:
96° + ∠CD = 148°
∠CD = 148° - 96°
∠CD = 52°
Answer:
ok dont get addicted
Step-by-step explanation:
Answer:
9 and 12
Step-by-step explanation:
hope this helps.