SOMEONE HELP ASAPPPPPPP!!! PLEASE
1 answer:
(1) See below for a diagram. Basically, the distance on the ground from the person to the building (34 ft) is adjacent to the angle of elevation (74 degrees) and the height of the building (labeled h in the diagram) is the side opposite the angle. Since we are dealing with opposite and adjacent we use the tangent of the angle and tan = opp/adj
Specifically,
<span class="_wysihtml5-temp-placeholder"></span>
feet.
Please be sure your calculator is set to degrees (not radians) when you do this problem.
(2) Here since P & Q are complimentary it means that their sum is 90 degrees. Since this is a right triangle that means that the remaining angle (R) must be the right angle. See below for a diagram.
sin = opp/hyp. As the sin Q = 9/41 this means that 9 is the length of the side opposite Q (the side PR) and 41 is the length of the hypotenuse. This makes the remaining side (QR) 40 in length.
cos = adj/hyp. If we focus on angle P the side adjacent (next to) is 9 and the hypotenuse is 41. Thus the cos of P = 9/41.
You could have also realized that if P & Q are complimentary the sin P = cos Q and the cos P = sin Q. We were not asked about tangent but it is also the case that tan P = cot Q and cot P = tan Q.
Specifically,
Please be sure your calculator is set to degrees (not radians) when you do this problem.
(2) Here since P & Q are complimentary it means that their sum is 90 degrees. Since this is a right triangle that means that the remaining angle (R) must be the right angle. See below for a diagram.
sin = opp/hyp. As the sin Q = 9/41 this means that 9 is the length of the side opposite Q (the side PR) and 41 is the length of the hypotenuse. This makes the remaining side (QR) 40 in length.
cos = adj/hyp. If we focus on angle P the side adjacent (next to) is 9 and the hypotenuse is 41. Thus the cos of P = 9/41.
You could have also realized that if P & Q are complimentary the sin P = cos Q and the cos P = sin Q. We were not asked about tangent but it is also the case that tan P = cot Q and cot P = tan Q.
You might be interested in
I'm assuming you mean #10?
So we're given this equation:
In this equation, we a variable of <em>b</em>. We want to solve for <em>b</em> by isolating it, or setting it alone. We see that on the side with <em>b</em> on it, it is being subtracted by 5. We want to the opposite in order to isolate <em>b</em>.
Remember that when you do one thing to one side of the equation, you must do it to the other side as well. We can add 5 on both sides to cancel out the negative 5 on the left.
Therefore we know that <em>b</em> does not equal -10, which can be represented as:
So you have to (a) color the hair yellow.
So we're given this equation:
In this equation, we a variable of <em>b</em>. We want to solve for <em>b</em> by isolating it, or setting it alone. We see that on the side with <em>b</em> on it, it is being subtracted by 5. We want to the opposite in order to isolate <em>b</em>.
Remember that when you do one thing to one side of the equation, you must do it to the other side as well. We can add 5 on both sides to cancel out the negative 5 on the left.
Therefore we know that <em>b</em> does not equal -10, which can be represented as:
So you have to (a) color the hair yellow.