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4 years ago

HELPP PLEASEEEEEEE ITS PROBS EASY FOR YOU GUYS

Chemistry

2 answers:

hichkok12 [17]4 years ago

5 0

Answer:

ik that energy makes us movie and that it powers lights and electronics

kinetic energy ,chemical energy ,potential energy ,and thermal energy

the law of conservation of energy states that the total energy of an isolated system remains constant

Explanation:

hope it helpss

eimsori [14]4 years ago

5 0

What do you know about energy?
Energy makes matter move or change.
What are two types?
There are two main categories kinetic and potential.
What is the law of conversation of energy?
the law that states that energy cannot be created or destroyed but can be changed from one form to another.

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Which is a property of all solids? A. Particles are far apart.

uysha [10]

The answer is B because none of the other options are true.

4 0

3 years ago

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At a certain temperature, 0.800 mol SO 3 is placed in a 1.50 L container. 2 SO 3 ( g ) − ⇀ ↽ − 2 SO 2 ( g ) + O 2 ( g ) At equil

Elanso [62]

Answer : The value of equilibrium constant (K) is, 0.004

Explanation :

First we have to calculate the concentration of $SO_3\text{ and }O_2$

$\text{Concentration of }SO_3=\frac{\text{Moles of }SO_3}{\text{Volume of solution}}=\frac{0.800mol}{1.50L}=1.2M$

and,

$\text{Concentration of }O_2=\frac{\text{Moles of }O_2}{\text{Volume of solution}}=\frac{0.150mol}{1.50L}=0.1M$

Now we have to calculate the value of equilibrium constant (K).

The given chemical reaction is:

$2SO_3(g)\rightarrow 2SO_2(g)+O_2(g)$

Initial conc. 1.2 0 0

At eqm. (1.2-2x) 2x x

As we are given:

Concentration of $O_2$ at equilibrium = x = 0.1 M

The expression for equilibrium constant is:

$K_c=\frac{[SO_2]^2[O_2]}{[SO_3]^2}$

Now put all the given values in this expression, we get:

$K_c=\frac{(2x)^2\times (x)}{(1.2-2x)^2}$

$K_c=\frac{(2\times 0.1)^2\times (0.1)}{(1.2-2\times 0.1)^2}$

$K_c=0.004$

Thus, the value of equilibrium constant (K) is, 0.004

3 0

4 years ago

What type of product forms in the intramolecular reaction between the aldehyde portion of the glucose molecule below and its C-5

djyliett [7]

Question:

What type of product forms in the intramolecular reaction between the aldehyde portion of the glucose molecule below and its C-5 hydroxyl group?

a. disaccharide

b. carboxylic acid

c. hemiacetal

d. ester

e. stereoisomer

Answer:

hemiacetal forms in the intramolecular reaction between the aldehyde portion of the glucose molecule and its C-5 hydroxyl group

Explanation:

It is an alcohol also an ether that has been attached to the carbon molecule. Here the hydrogen has occupied the fourth bonding position. This hemiacetal has been derived from the aldehyde. Hence, hemiketal being an alcohol as well as ether has been attached to the same carbon and also to the two other carbon.

7 0

3 years ago

Why do solids have a fixed shape and fixed volumes ?

Artist 52 [7]

Because their atoms and molecules are held together firmly by the strong inter molecular forces

6 0

3 years ago

In chemistry what is nickle (II) nitrate solution mixed with a sodium hydroxide solution

AlladinOne [14]

Answer:

I hope this will help you and Please mark me as Brilliant

Explanation:

Approximately 2 mL of Solution A (on the left) is added to a sample of Solution B (on the right) with a dropping pipet. If a precipitate forms, the resulting precipitate is suspended in the mixture. The mixture is then stirred with a glass stirring rod and the precipitate is allowed to settle for about a minute.

Solution A: 0.5 M sodium hydroxide, colorless

Solution B: 0.2 M nickel(II) nitrate, green

Precipitate: light green

Ni(NO3)2(aq) + 2 NaOH(aq) —> Ni(OH)2(s) + 2 NaNO3(aq)

Credits:

Design

Kenneth R. Magnell Central Michigan University, Mt. Pleasant, MI 48859

John W. Moore University of Wisconsin - Madison, Madison, WI 53706

Video

Jerrold J. Jacobsen University of Wisconsin - Madison, Madison, WI 53706

Text

Kenneth R. Magnell Central Michigan University, Mt. Pleasant, MI 48859

6 0

3 years ago