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k0ka [10]
2 years ago
9

Which of the following has the greatest mass?

Chemistry
1 answer:
Annette [7]2 years ago
8 0

Answer:

I guess one mole. of mercury

Explanation:

because mercury is denser

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What are common names for antimony ? for science
dusya [7]

Antimony is a chemical element with symbol Sb (from Latin: stibium) and atomic number 51. A lustrous gray metalloid, it is found in nature mainly as the sulfide mineral stibnite (Sb2S3). Antimony compounds have been known since ancient times and were powdered for use as medicine and cosmetics, often known by the Arabic name, kohl.

4 0
3 years ago
A compound has an empirical formula of
Ksju [112]

Answer: C12H12N2O2 (Cyclomethyltryptophan)

8 0
2 years ago
Read 2 more answers
Zinc sulfate is a 2-ion electrolyte,
Gekata [30.6K]

<u>Answer:</u> The value of <em>i</em> is 1.4 and 40% dissociation of 100 particles of zinc sulfate will yield 60 undissociated particles.

<u>Explanation:</u>

The equation used to calculate the Vant' Hoff factor in dissociation follows:

\alpha =\frac{i-1}{n-1}

where,

\alpha = degree of dissociation = 40% = 0.40

i = Vant' Hoff factor

n = number of ions dissociated = 2

Putting values in above equation, we get:

0.40=\frac{i-1}{2-1}\\\\0.40=i-1\\\\i=1.4

The equation used to calculate the degee of dissociation follows:

\alpha =\frac{\text{Number of particles dissociated}}{\text{Total number of particles taken}}

Total number of particles taken = 100

Degree of dissociation = 40% = 0.40

Putting values in above equation, we get:

0.40=\frac{\text{Number of particles dissociated}}{100}\\\\\text{Number of particles dissociated}=(0.40\times 100)=40

This means that 40 particles are dissociated and 60 particles remain undissociated in the solution.

Hence, 40% dissociation of 100 particles of zinc sulfate will yield 60 undissociated particles.

7 0
2 years ago
Lewis dot structure for SeO
padilas [110]

Answer:

selenium dioxide

Explanation:

8 0
3 years ago
What is the mass of oxygen that can be produced from 2.79 moles of lead(ll) nitrate
denis23 [38]

1.38 moles of oxygen

Explanation:

Thermal decomposition of Lead (II) nitrate is shown by the balanced equation below;

2Pb(NO₃)₂ → 2PbO + 4NO₂ + O₂

The mole ration of Lead (II) nitrate to oxygen is 2: 1

Therefore 2.76 moles of  Lead (II) nitrate will lead to production of? moles of oxygen;

2: 1

2.76: x

Cross-multiply;

2x = 2.76 * 1

x = 2.76 / 2

x = 1.38

8 0
3 years ago
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