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yuradex [85]
3 years ago
9

The analysis of 2.12 of a compound gave 0.33 of carbon, 1.82 of the same compound gave 1.53 of sulphur. Calculate the emperical

formula
Chemistry
1 answer:
luda_lava [24]3 years ago
6 0

Answer:

CS₂

Explanation:

To find the empirical formula we need to determine first the percentage of each atom in the molecule. Then, we need to find the moles and, as empirical formula is the simplest whole-number ratio of atoms we can solve the empirical formula:

<em>%C:</em>

0.33gC / 2.12g * 100 = 15.6%

<em>%S:</em>

1.53g S / 1.82g * 100 = 84.1%

In a basis of 100, the moles of each atom are:

<em>C:</em>

15.6g C * (1mol / 12.01g) = 1.30 moles

<em>S:</em>

84.1g S * (1mol / 32.065g) = 2.62 moles

The ratio of Sulphur-Carbon is:

2.62mol / 1.30mol = 2

That means empirical formula is:

<h3>CS₂</h3>
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Answer:

Explanation:

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For example,

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The chemical property of iron is to react with oxygen and form rust. This process or chemical change is called corrosion. So corrosion is chemical change.

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7 0
3 years ago
A laboratory analysis of an unknown sample yields 40.5% carbon, 4.5% hydrogen, and 55.0% oxygen. if the sample has a molar mass
den301095 [7]
Answer is: molecular formula is C₆H₈O₆.
n(C) = m(C) ÷ M(C).
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n(C) = 3,375 mol.
n(H) = m(H) ÷ M(H).
n(H) = 4,5 g ÷ 1 g/mol.
n(H) = 4,5 mol.
n(O) = m(O) ÷ M(O).
n(O) = 55 g ÷ 16 g/mol.
n(O) = 3,4 mol.
n(C) : n(H) : n(O) = 3,375 mol : 4,5 mol : 3,4 mol / :3,375.
n(C) : n(H) : n(O) = 1 : 1,33 : 1.
n(C) : n(H) : n(O) = 3 : 4 : 3.
M(C₃H₄O₃) = 88 g/mol · 2 = 176 g/mol.

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Dima020 [189]

Answer:

See the explanation below, please.

Explanation:

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3 years ago
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SVETLANKA909090 [29]

Answer:

Explanation:

1. Please provide the enthalpy info - I will work on it with the info

2.

i) Reaction a should be modified to match the number of S in equation:

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ii) Reaction b should be written reversely to match the reactants of SO2:

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iii) Adding the equations together:

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iv) Enthalpy of the combined reaction = -370+256 = -114kJ

 It is negative so the reaction is exothermic.

5 0
3 years ago
Read 2 more answers
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