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yuradex [85]
3 years ago
9

The analysis of 2.12 of a compound gave 0.33 of carbon, 1.82 of the same compound gave 1.53 of sulphur. Calculate the emperical

formula
Chemistry
1 answer:
luda_lava [24]3 years ago
6 0

Answer:

CS₂

Explanation:

To find the empirical formula we need to determine first the percentage of each atom in the molecule. Then, we need to find the moles and, as empirical formula is the simplest whole-number ratio of atoms we can solve the empirical formula:

<em>%C:</em>

0.33gC / 2.12g * 100 = 15.6%

<em>%S:</em>

1.53g S / 1.82g * 100 = 84.1%

In a basis of 100, the moles of each atom are:

<em>C:</em>

15.6g C * (1mol / 12.01g) = 1.30 moles

<em>S:</em>

84.1g S * (1mol / 32.065g) = 2.62 moles

The ratio of Sulphur-Carbon is:

2.62mol / 1.30mol = 2

That means empirical formula is:

<h3>CS₂</h3>
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fomenos

About 46.1 pounds of apple would be needed per day of the trip.

I managed to extract the complete scenario from the attached image.

The trip is made up of 4 men and 3 women, making a total of 7 people.

Everyone has become accustomed to 1500 calories per day.

The total calories needed per day for 7 persons = 1500 x 7

                           = 10,500 calories

189 g of apple has only 95 calories, what g of apple will produce 10,500 calories?

                 = 10,500 x 189/95 = 20,889.67 g of apple

From conversion:

1 g = 0.00220462 pounds

20,889.67 g = 20,889.67 x 0.00220462

                         = 46.1 pounds of apple

More about dimensional analysis can be found here: brainly.com/question/22015862

8 0
3 years ago
How can chloroform dissolve in water? Include information about molecular shape and polarity.
suter [353]

Answer:

You can dissolve about 1g of chloroform in a 100g of water; slightly less if the water is hot. This would not generally be considered 'soluble', but it's not entirely negligible either, depending on your purposes. chloroform is insoluble in water since it does not have any hydrophillic groups.

hope this helps you uwu

4 0
3 years ago
You wish to calculate the mass of hydrogen gas that can be prepared from 4.93 g of srh2 and 4.14 g of h2o.
Ivenika [448]
The maximum amount of hydrogen gas that can be prepared is if all the hydrogen from both compounds is released.

The hydrogen in 4.94 g of SrH2 is calculated from the mass ratios between Sr and H

1) H2 in SrH2

Sr atomic mass = 87.62 g/mol

H2 molar mass = 2.02 g/mol

Mass of 1 mol of SrH2 = 87.62 g / mol + 2.02 g/mol = 89.64 g/mol

Ratio of H2 to SrH2 = 2.02 g H2 / 89.64 g SrH2

Proportion: 2.02 g H2 / 89.64 gSrH2 = x / 4.93 g SrH2

=> x = 4.93 g SrH2 * 2.02 g H2 / 89.64 g SrH2 = 0.111 g H2

2) H2 in H2O

2.02 g H2 / 18.02 g H2O * 4.14 g H2O = 0.464 g H2

3) Total mass of hydrogen = 0.111 g + 0.464 g = 0.575 g

Answer: 0.575 g
7 0
3 years ago
What is located at the singularity of a black hole?
charle [14.2K]
The entire mass of a black hole
5 0
3 years ago
The mole fraction of NaCl in an aqueous solution is 0.132. What is the weight/weight percent of NaCl in this solution?
Marrrta [24]

Answer:

\% w/w=33.1\%

Explanation:

Hello,

In this case, since the solution is formed by sodium chloride and water, we understand that for one mole of solution, we have 0.132 moles of sodium chloride and 0.868 moles of water, therefore, by using their molar masses we can compute their masses in the solution:

m_{NaCl}=0.132molNaCl*\frac{58.44gNaCl}{1molNaCl}=7.714gNaCl\\ \\m_{H_2O}=0.868molH_2O*\frac{18gH_2O}{1molH_2O}=15.624gH_2O

Thereby, we can compute the weight/weight percent as follows:

\% w/w=\frac{m_{NaCl}}{m_{H_2O}+m_{NaCl}}*100\%

So we use the previously computed masses:

\% w/w=\frac{7.714g}{7.714g+15.624g}*100\%  \\\\\% w/w=33.1\%

Best regards.

4 0
4 years ago
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