Weight of one large bead is 1.5 grams and weight of one small bead is 8.75 grams.
Step-by-step explanation:
Let,
Weight of one large bead = x
Weight of one small bead = y
According to given statement;
12x+8y=88 Eqn 1
5x+2y=25 Eqn 2
Multiplying Eqn 2 by 4
![4(5x+2y=25)\\20x+8y=100\ \ \ Eqn\ 3\\](https://tex.z-dn.net/?f=4%285x%2B2y%3D25%29%5C%5C20x%2B8y%3D100%5C%20%5C%20%5C%20Eqn%5C%203%5C%5C)
Subtracting Eqn 1 from Eqn 3
![(20x+8y)-(12x+8y)=100-88\\20x+8y-12x-8y=12\\8x=12](https://tex.z-dn.net/?f=%2820x%2B8y%29-%2812x%2B8y%29%3D100-88%5C%5C20x%2B8y-12x-8y%3D12%5C%5C8x%3D12)
Dividing both sides by 8
![\frac{8x}{8}=\frac{12}{8}\\x=1.5](https://tex.z-dn.net/?f=%5Cfrac%7B8x%7D%7B8%7D%3D%5Cfrac%7B12%7D%7B8%7D%5C%5Cx%3D1.5)
Putting x=1.5 in Eqn 1
![12(1.5)+8y=88\\18+8y=88\\8y=88-18\\8y=70](https://tex.z-dn.net/?f=12%281.5%29%2B8y%3D88%5C%5C18%2B8y%3D88%5C%5C8y%3D88-18%5C%5C8y%3D70)
Dividing both sides by 8
![\frac{8y}{8}=\frac{70}{8}\\y=8.75](https://tex.z-dn.net/?f=%5Cfrac%7B8y%7D%7B8%7D%3D%5Cfrac%7B70%7D%7B8%7D%5C%5Cy%3D8.75)
Weight of one large bead is 1.5 grams and weight of one small bead is 8.75 grams.
Keywords: linear equation, elimination method
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The area of a circle uses the radius of a circle, which is 1/2 the diameter.
In the calculation the radius is squared.
Since the diameter of the larger circle is twice as large the radius would be 2 times.
2 squared would be: 2^2 = 4
This means the area of the larger circle is 4 times larger which would make the ratio 4:1
Answer:
1 4/35
Step-by-step explanation:
All I did was do 5/7 + 2/5.