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2 years ago

MATH, please help! I don’t understand

Mathematics

1 answer:

Westkost [7]2 years ago

4 0

Answer:

The first option is correct

Step-by-step explanation:

Surface area for a cylinder: $2\pi r^2+2\pi rh$

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Lines p and q are crossed by transversal s. Classify 1 and 5

allsm [11]

Answer:

corresponding angles

Step-by-step explanation:

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2 years ago

Please help I’m confused

Amanda [17]

Answer:

First 3 boxes down are Vertical, Complementary, Supplementary . Second 3 Boxes Down Are add up to 90 degrees, add up to 180 degrees, and are congruent.

I hope this helps :)

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1 year ago

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The area of a rectangular swimming pool is 360 square feet. If the length of the swimming pool is 9 feet more than its width, fi

Inessa [10]

Answer:

l = 24ft

Step-by-step explanation:

A = lw

360 = (x + 9)(x)

360 = x^2 + 9x

0 = x^2 + 9x - 360

0 = (x + 24)(x - 15)

x ≠ -24 (length cannot be negative)

x = 15

l = 15 + 9

l = 24ft

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2 years ago

help me find the volume and area of this figure step by step pleasefyi the answer key my teacher gave me says that the surface a

alisha [4.7K]

The volume of the shape

We have a cylinder that is cut into two. Its external radius is 5ft, while its internal radius is 4ft.

External radius = internal radius + thickness

$\begin{gathered} \text{External radius = 4ft + 1ft } \\ =\text{ 5ft} \end{gathered}$

Internal radius = 4ft (given)

Recall that the volume(V) of a full cylinder is:

$V\text{ = }\pi r^2h$

Since the cylinder is cut into two, the volume(V) is:

$V\text{ = }\frac{\pi r^2h}{2}$

height (h) = 12ft (given)

The volume of the shape:

$\begin{gathered} =\text{ Volume of cylinder with a radius of 5ft - Volume of cylinder with a radius of 4ft} \\ =\text{ }\frac{\pi\text{ }\times5^2\text{ }\times\text{ 12}}{2}\text{ - }\frac{\pi\text{ }\times4^2\text{ }\times\text{ 12}}{2} \\ =\text{ 471.239 - }301.593 \\ =169.65ft^3 \end{gathered}$

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4 months ago

How many 60 degree angles does it take to make a full turn?

Ksenya-84 [330]

It take 6 60 degree turn to do a full turn

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2 years ago

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