since its the zeros it should be x -/+ something
(x-1)(x+1)(x+4)
multiply for standard form
((x^2)-1)(x+4)
x^3-x
+ x^2 -4
x^2 + x^2 -x -4
43. 9 + 10 + 13 + 13 = $45
45 - 1 = 44
44 x 4 = 176
176 + 8 = 184
184/4 = 46
46 tokens per person
44. a. 22 x 5 = 110
943/110 = 8.7
you will need 9 bookcases
b. 110 x 9 = 990
990 - 943 = 47
47 - 44 = 3
There will be 3 books on the third shelf.
9514 1404 393
Answer:
B, C
Step-by-step explanation:
The sums are ...
A) 59.45
B) 118.16
C) 18.97
D) 27.76
Sums B and C have 8 in the ones place.
__
You can add the ones-place digits. If the resulting ones-digit is 7 or 8, then add the tenths-place digits. If the carry from that sum, added to the sum of ones-place digits, gives a value of 8 or 18, then you found a sum with a ones digit of 8.
Answer:
32.6
Step-by-step explanation:
Look at the decimal in the hundredths place in 32.62
If the number is 0-4, round down. If the number is 5-9, round up.
In 32.62, the number in the hundredths place is 2. So, we round down to 32.6
I'm assuming you meant to write a^4 = 625.
If that is the case, then note how 625 = 25^2, and how a^4 is the same as (a^2)^2
So we go from this
a^4 = 625
to this
(a^2)^2 = 25^2
Apply the square root to both sides and you'll end up with: a^2 = 25
From here, apply the square root again to end up with the final answer: a = 5 or a = -5
As a check:
a^4 = (-5)^4 = (-5)*(-5)*(-5)*(-5) = 25*25 = 625
a^4 = (5)^4 = (5)*(5)*(5)*(5) = 25*25 = 625
Both values of 'a' work out
