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Korvikt [17]
3 years ago
7

What is the simplified expression for 2 power 2 multiplied by 2 power 3 over 2 power 4?

Mathematics
2 answers:
mr_godi [17]3 years ago
8 0
Im not sure about those answers! But here is what i got !

Grace [21]3 years ago
3 0

Answer:

Option 2 - \frac{2^2\times 2^3}{2^4}=2^{1}

Step-by-step explanation:

Given : Expression '2 power 2 multiplied by 2 power 3 over 2 power 4'.

To find : What is the simplified expression ?

Solution :

Writing expression in numeric form,

'2 power 2 multiplied by 2 power 3 over 2 power 4',

i.e. \frac{2^2\times 2^3}{2^4}

Solving the expression,

As, x^a\times x^b=x^{a+b}

\frac{2^2\times 2^3}{2^4}=\frac{2^{2+3}}{2^4}

\frac{2^2\times 2^3}{2^4}=\frac{2^{5}}{2^4}

As, \farc{x^a}{x^b}=x^{a-b}

\frac{2^2\times 2^3}{2^4}=2^{5-4}

\frac{2^2\times 2^3}{2^4}=2^{1}

\frac{2^2\times 2^3}{2^4}=1

Therefore, The option 2 is correct.

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Aleks [24]
The sum clearly diverges. This is indisputable. The point of the claim above, that

1+2+3+\cdots=-\dfrac1{12}

is to demonstrate that a sum of infinitely many terms can be manipulated in a variety of ways to end up with a contradictory result. It's an artifact of trying to do computations with an infinite number of terms.

The mathematician Srinivasa Ramanujan famously demonstrated the above as follows: Suppose the series converges to some constant, call it C. Then

\begin{matrix}C&=&1&+2&+3&+4&+5&+6&+\cdots\\4C&=&&+4&&+8&&+12&+\cdots\\-3C&=&1&-2&+3&-4&+5&-6&+\cdots\end{matrix}

Now, recall the geometric power series

\displaystyle\sum_{n\ge0}x^n=1+x+x^2+x^3+\cdots=\dfrac1{1-x}

which holds for any |x|. It has derivative

\displaystyle\sum_{n\ge1}nx^{n-1}=1+2x+3x^2+4x^3+\cdots=\dfrac1{(1-x)^2}

Taking x=-1, we end up with

1+2(-1)+3(-1)^2+4(-1)^3+\cdots=1-2+3-4+\cdots=\dfrac14

and so

-3C=\dfrac14\implies C=-\dfrac1{12}

But as mentioned above, neither power series converges unless |x|. What Ramanujan did was to consider the sum 1-2+3-4+\cdots as a limit of the power series evaluated at x=-1:

\displaystyle-3C=\lim_{x\to-1^+}\sum_{n\ge1}nx^{n-1}=\lim_{x\to-1^+}\frac1{(1-x)^2}=\frac14

then arrived at the conclusion that C=-\dfrac1{12}.

But again, let's emphasize that this result is patently wrong, and only serves to demonstrate that one can't manipulate a sum of infinitely many terms like one would a sum of a finite number of terms.
4 0
3 years ago
Which is one way to check 102 : 6 = 17?
MArishka [77]

Answer:

One way to check is 102 ÷ 6 = 17 is 100 ÷ 5 = 20. 

7 0
3 years ago
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3 years ago
Please help!!!!! this worksheet is due by the end of class​
Rainbow [258]

Answer:

Slope: 6

y-intercept: 8

x-intercept: -4/3

Step-by-step explanation:

Isolate the y. Note the equal sign, what you do to one side, you do to the other. First, divide 2 from both sides:

(2y - 6x - 8)/2 = (0)/2

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Isolate the variable, y. Add 6x and 8 to both sides:

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y = 0 + 6x + 8

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The slope intercept form is: y = mx + b, in which m = slope, and b = y-intercept.

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y-intercept: 8

To find the x-intercept, plug in 0 for y in the equation:

y = 6x + 8

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Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

First, subtract 8 from both sides:

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Isolate the variable, x. Divide 6 from both sides:

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Is the number 10 odd or even?
Lubov Fominskaja [6]
Hello there!

The number 10 is an even number.


Hope this helps and have a great day! :)
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