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Brums [2.3K]
3 years ago
12

There are 45 female performers in a dance recital. The ratio of men to women is 7:9. How many men are in the dance recital? Ther

e are _____ men in the dance recital.
Mathematics
2 answers:
Viefleur [7K]3 years ago
7 0

Answer:

35

Step-by-step explanation:

-BARSIC- [3]3 years ago
3 0

Answer:

35 men

Step-by-step explanation:

To solve, you can divide 45/9 which you get 5. After you get 5, multiply that by 7 and you get 35. Hope this helps

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at a conference of 250 people, 30% of the participants are french, 35% are americans, 20% are germans, and the rest are of the o
Lady bird [3.3K]
Ok...we got 250 people
30% are French, 35% are Americans, 20% are Germans....thats 85%.
This means 15% are from other countries

3 not from other countries...
0.85 * 0.85 * 0.85 = 0.6

0.6(250) = 150 students <===
5 0
3 years ago
If AD=6 and AB=24, find AC
ruslelena [56]
When a perpendicular is dropped from the right-angle (C) to the opposite side AB, the metric relations apply:
BD*BA=a^2 ..........................(1)
AD*AB=b^2...........................(2)
BD*DA=DC^2........................(3)

Given AD=6, AB=24, using metric relation (2) above, we have
b^2=6*24=144
=>
b=sqrt(144)=12

By the way, we conclude that this is a 30-60-90 triangle because b/AB=(1/2)=sin(B) => B=30 degrees.

Answer: b=12
6 0
3 years ago
Assume that there are 2 trials.
vampirchik [111]
Answer: The p(success) = 0.6

Your question is a little unclear, but I believe you are asking about the probability that at least one of the trials in the experiment were successful.

If that is the case, you simply have to add the probability of 1 success with the probability of 2 successes.

That is 0.48 +  0.16 = 0.64

Rounding our answer to one decimal place gives us 0.6.
7 0
3 years ago
Read 2 more answers
The tables represent two linear functions in a system,
Alenkasestr [34]

Answer:

<h2>(8, -22)</h2>

Step-by-step explanation:

The slope-intercept form of an equation of a line:

y=mx+b

m - slope

b - y-intercept

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

First table:

(-4, 26), (0, 10) → b = 10

m=\dfrac{10-26}{0-(-4)}=\dfrac{-16}{4}=-4

\boxed{y=-4x+10}

Second table:

(-4, 14), (0, 2) → b = 2

m=\dfrac{2-14}{0-(-4)}=\dfrac{-12}{4}=-3

\boxed{y=-3x+2}

We have the system of equations:

\left\{\begin{array}{ccc}y=-4x+10&(1)\\y=-3x+2&(2)\end{array}\right\\\\\text{Put (1) to (2):}\\\\-4x+10=-3x+2\qquad\text{subtract 10 from both sides}\\-4x=-3x-8\qquad\text{add 3x to both sides}\\-x=-8\qquad\text{change the signs}\\x=8\\\\\text{Put the value of x to (2):}\\\\y=-3(8)+2\\y=-24+2\\y=-22

5 0
3 years ago
Help ASAP!!!! Please someone help me
frosja888 [35]

Answer:

1 9/8

Step-by-step explanation:

Its a lot of explaining lol

8 0
3 years ago
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