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3 years ago

13

A bakery sold 31 bagels in the first hour of business and 42 bagels in the second hour .If the bakery had 246 bagels to start wi

th, how many bagels were left after the second hour

1 answer:

Zielflug [23.3K]3 years ago

4 0

Answer:

173 bagels are left

Step-by-step explanation:

31+42=73

246-73=173

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A remote control car races straight down the street at 26 miles per hour. Two

WINSTONCH [101]

Answer:

C.

Step-by-step explanation:

In order to find when the other car catches up to the other, you need to graph the distance and time for both cars. The linear function will represent their rate of speed, when the lines intersect, that is when car 2 catches up to car 1.

Hope this helps.

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3 years ago

Determine if it is possible to form a triangle with the given side lengths. 7 yd, 8 yd, 9 yd

Dimas [21]

Answer:

yes it is possible to make a triangle with those lengths.

6 0

3 years ago

Use the Chain Rule to find the indicated partial derivatives. z = x^4 + xy^3, x = uv^4 + w^3, y = u + ve^w Find : ∂z/∂u , ∂z/∂v

k0ka [10]

I'll use subscript notation for brevity, i.e. $\frac{\partial f}{\partial x}=f_x$ .

By the chain rule,

$z_u=z_xx_u+z_yy_u$

$z_v=z_xx_v+z_yy_v$

$z_w=z_xx_w+z_yy_w$

We have

$z=x^4+xy^3\implies\begin{cases}z_x=4x^3+y^3\\z_y=3xy^2\end{cases}$

and

$\begin{cases}x=uv^4+w^3\\y=u+ve^w\end{cases}\implies\begin{cases}x_u=v^4\\x_v=4uv^3\\x_w=3w^2\\y_u=1\\y_v=e^w\\y_w=ve^w\end{cases}$

When $u=1,v=1,w=0$ , we have

$\begin{cases}x(1,1,0)=1\\y(1,1,0)=2\end{cases}\implies\begin{cases}z_x(1,2)=12\\z_y(1,2)=12\end{cases}$

and the partial derivatives take on values of

$\begin{cases}x_u(1,1,0)=1\\x_v(1,1,0)=4\\x_w(1,1,0)=0\\y_u(1,1,0)=1\\y_v(1,1,0)=1\\y_w(1,1,0)=1\end{cases}$

So we end up with

$\boxed{\begin{cases}z_u(1,1,0)=24\\z_v(1,1,0)=60\\z_w(1,1,0)=12\end{cases}}$

3 0

3 years ago

Solve for Y. 9/4y-12=1/4y-4

Lelechka [254]

I believe y equals 4.

9/4y - 12. = 1/4y - 4
+ 12. +12
9/4y. = 1/4y + 8
- 1/4y. - 1/4y

8/4y. = 8
2y. = 8
2. 2
Y = 4

4 0

4 years ago

Read 2 more answers

VashaNatasha [74]

Answer:

1. z = -15

2. p = 7

3. h = -11

4. t = 14

5. q = 12

Step-by-step explanation:

1.

$\frac{z}{-5}+1=4$

Add -1 both sides,

$\frac{z}{-5}+1-1=4-1\\\frac{z}{-5}=3$

Multiply both sides by -5,

$\frac{z}{-5}\times-5=3\times-5\\z=-15$

2.

Distribute 3 in $p+2$ and then add -6p and -6 both sides.

$3(p+2)=6p-15\\3\times p+3\times2 = 6p-15\\3p+6=6p-15\\3p-6p=-15-6\\-3p=-21\\p=\frac{-21}{-3}=7$

3.

$\frac{h-7}{2}=3(h+8)$

Multiply both sides by 2,

$\frac{h-7}{2}\times2=3(h+8)\times2\\h-7=6(h+8)\\h-7=6h+48$

Add -6h and 7 both sides,

$h-6h-7+7=6h-6h+48+7\\-5h=55\\h=\frac{55}{-5}\\h=-11$

4.

$4t+2-5=3(t+7)-9\\4t-3=3t+21-9\\4t-3=3t+12$

Add -3t and 3 both sides.

$4t-3t-3+3=3t-3t+12+3\\t=15$

5.

$2(q-4)=4(q-8)\\2q-8=4q-32$

Add -2q and 8 both sides.

$2q-8-4q+8=4q-4q-32+8\\-2q=-24\\q=\frac{-24}{-2}\\q=12$

Therefore,

1. z = -15

2. p = 7

3. h = -11

4. t = 14

5. q = 12

4 0

4 years ago