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4 years ago

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The linear density of a string is 1.4 × 10-4 kg/m. A transverse wave on the string is described by the equation y = (0.026 m) si

n[(1.0 m-1)x + (38 s-1)t] What are (a) the wave speed and (b) the tension in the string?

1 answer:

Elena L [17]4 years ago

7 0

Answer:

92

Explanation:

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(TCO-8) A band-pass filter has fC1 = 5 kHz and fC2 = 88 kHz. Calculate Bandwidth (BW) and center frequency (fo) for this filter.

Temka [501]

Bandwidth is the difference between the upper and lower frequencies in a continuous band of frequencies.

Mathematically can be expressed as,

$BW = F_{c2}-F_{c1}$

The upper frequency is 88Hz and the lower frequency is 6, therefore the Bandwidth would be,

$BW = (88-5)kHz$

$BW = 83kHz$

The center frequency is given on the basis of the square root of the multiplication of the two reference frequencies, then,

$f_0 = \sqrt{f_{c1}*f_{c2}}$

$f_0 = \sqrt{88*5}$

$f_0 = 20.97kHz$

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3 years ago

where would information on the chemical and physical properties of a specific chemical be located in a laboratory or in the work

goldenfox [79]

Answer:

Both

Explanation:

8 0

3 years ago

The perihelion of the comet TOTAS is 1.69 AU and the aphelion is 4.40 AU. Given that its speed at perihelion is 28 km/s, what is

dybincka [34]

Answer:

The speed at the aphelion is 10.75 km/s.

Explanation:

The angular momentum is defined as:

$L = mrv$ (1)

Since there is no torque acting on the system, it can be expressed in the following way:

$t = \frac{\Delta L}{\Delta t}$

$t \Delta t = \Delta L$

$\Delta L = 0$

$L_{a} - L_{p} = 0$

$L_{a} = L_{p}$ (2)

Replacing equation 1 in equation 2 it is gotten:

$mr_{a}v_{a} =mr_{p}v_{p}$ (3)

Where m is the mass of the comet, $r_{a}$ is the orbital radius at the aphelion, $v_{a}$ is the speed at the aphelion, $r_{p}$ is the orbital radius at the perihelion and $v_{p}$ is the speed at the perihelion.

From equation 3 v_{a} will be isolated:

$v_{a} = \frac{mr_{p}v_{p}}{mr_{a}}$

$v_{a} = \frac{r_{p}v_{p}}{r_{a}}$ (4)

Before replacing all the values in equation 4 it is necessary to express the orbital radius for the perihelion and the aphelion from AU (astronomical units) to meters, and then from meters to kilometers:

$r_{p} = 1.69 AU x \frac{1.496x10^{11} m}{1 AU}$ ⇒ $2.528x10^{11} m$

$r_{p} = 2.528x10^{11} m x \frac{1km}{1000m}$ ⇒ $252800000 km$

$r_{a} = 4.40 AU x \frac{1.496x10^{11} m}{1 AU}$ ⇒ $6.582x10^{11} m$

$r_{p} = 6.582x10^{11} m x \frac{1km}{1000m}$ ⇒ $658200000 km$

Then, finally equation 4 can be used:

$v_{a} = \frac{(252800000 km)(28 km/s)}{(658200000 km)}$

$v_{a} = 10.75 km/s$

Hence, the speed at the aphelion is 10.75 km/s.

8 0

3 years ago

When an object oscillating in simple harmonic motion is at its maximum displacement from the equilibrium position. What are its

xxMikexx [17]

Answer:

Speed = 0

Restoring force = maximum

Explanation:

Suppose this situation as a spring with a mass attached to it, that oscilates.

The force that the spring does (the restoring force in this case) is something like

F = K*L

where K is the constant of the spring, and L is the difference between the length of the spring (stretched) and the length of the spring at rest.

Then, when the harmonic oscillator is at its maximum displacement, L takes its maximum value, which means that at this point the restoring force must also have a maximum.

And for the velocity, at this point we have the maximum displacement, this means that, if the mass was moving to the right, after this point the mass stops going to the right, and then returns to the equilibrium position to the left.

Then the velocity has a change of sign, (like an object that reached its maximum height) this means that at that exact moment, the velocity must be zero.

Then:

Speed = 0

Restoring force = maximum

6 0

3 years ago

The equivalent resistance of two resistors connected in series is always greater than the equivalent resistance of the same two

seraphim [82]

Answer:

True

Explanation:

Because the resistors in series is the sum of the two resistors given as

R= R1+R2

While that of resistors in parallel is the sum of the reciprocal of the resistance given as

1/R = 1/ R1+ 1/R2

So that of series connection will be greater

4 0

3 years ago