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pshichka [43]
3 years ago
12

According to Newton's 3rd law of motion, an action creates _____.

Physics
2 answers:
Katena32 [7]3 years ago
7 0

it's (c) an equal and opposite reaction

miv72 [106K]3 years ago
5 0
C.an equal and opposite reaction
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A rocket passes you at a speed of 0.85c, and you measure its length to be 35.0 m. What is its measured length when at rest?
viktelen [127]

Answer:

66.4 m

Explanation:

To solve the problem, we can use the length contraction formula, which states that the length observed in the reference frame moving with the object (the rocket) is given by

L=L_0 \sqrt{1-(\frac{v}{c})^2}

where

L_0 is the proper length (the length measured from an observer at rest)

v is the speed of the object (the rocket)

c is the speed of light

Here we know

v = 0.85c

L = 35.0 m

So we can re-arrange the equation to find the length of the rocket at rest:

L_0 = \frac{L}{\sqrt{1-(\frac{v}{c})^2}}=\frac{35.0}{\sqrt{1-(\frac{0.85c}{c})^2}}=66.4 m

8 0
3 years ago
The light of that star actually gives off
ICE Princess25 [194]
-I believe the star gives off energy-, With<span> most </span>stars<span>, like our sun, hydrogen </span>is<span> being converted into Helium, a process which gives </span>off<span> energy that heats the </span>star<span>.</span>
7 0
3 years ago
Read 2 more answers
A positive charge +q1 is located to the left of a negative charge -q2. On a line passing through the two charges, there are two
AfilCa [17]

Answer:

please the answer below

Explanation:

(a) If we assume that our origin of coordinates is at the position of charge q1, we have that the potential in both points is

V_1=k\frac{q_1}{r-1.0}-k\frac{q_2}{1.0}=0\\\\V_2=k\frac{q_1}{r+5.2}-k\frac{q_2}{5.2}=0\\\\

k=8.89*10^9

For both cases we have

k\frac{q_1}{r-1.0}=k\frac{q_2}{1.0}\\\\q_1(1.0)=q_2(r-1.0)\\\\r=\frac{q_1+q_2}{q_2}\\\\k\frac{q_1}{r+5.2}=k\frac{q_2}{5.2}\\\\q_1(5.2)=q_2(r+5.2)\\\\r=\frac{5.2q_1-5.2q_2}{q_2}

(b) by replacing this values of r in the expression for V we obtain

k\frac{q_1}{\frac{5.2(q_1-q_2)}{q_2}+5.2}=k\frac{q_2}{5.2}\\\\\frac{q_1}{q_2}=\frac{(q_1-q_2)}{q_2}-1.0=\frac{q_1-q_2-q_2}{q_2}=\frac{q_1-2q_2}{q_2}

hope this helps!!

3 0
3 years ago
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If the wavelength of a 4.65 ✕ 102 Hz sound in freshwater is 3.45 m, what is the speed of sound in fresh water?
natima [27]

Answer:

Explanation:

Given that, the wavelength is 3.45m

λ=3.45m

Frequency is 4.65×10^2Hz

F=4.65×10^2Hz

Speed is given as

V=Fλ

Then,

V=4.65×10^2× 3.45

V=1604.25m/s

The speed of sound in fresh water is 1604.25m/s

8 0
3 years ago
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The speed of light is now defined to be c-2.99792458 x 10^8 m/s
Harman [31]
Yes, that statement is loaded with veracity, and is true as well. Did you have a question to ask ?
8 0
3 years ago
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