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ser-zykov [4K]
3 years ago
11

You want high availability for DHCP services, a primary server to handle most DHCP requests, and a secondary server to respond t

o client requests only if the primary server fails to in about a second. The primary server has about 85% of the IP addresses to lease, leaving the secondary server with about 15%. You don't want the servers to replicate with each other.What should you configure?
Computers and Technology
1 answer:
babymother [125]3 years ago
5 0

Answer:

The blocking system.

Explanation:

In order to avoid servers to replicate with each other, I should configure the blocking system of the first DHCP.

For example, if the first DHCP fails to respond, the second will get in place, however, I have to configure the first system that immediately that the second DHCP starts working, the first blocks its information and use.

By this way, there won´t be any duplicated actions or reponses.

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A. defragging your hard drive
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A company uses DHCP servers to dynamically assign IPv4 addresses to workstations. The address lease duration is set as 5 days. A
nikitadnepr [17]

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FF-FF-FF-FF-FF-FF and 255.255.255.255

Explanation:

FF-FF-FF-FF-FF-FF can be defined as the layer 2 address broadcast which is often used on ethernet frames as well as help to broadcast all equipment due to the fact broadcast is made possible through Ethernet networks in which the Frames are addressed to reach every computer system on a given LAN segment as far as they are addressed to MAC address FF:FF:FF:FF:FF:FF.

255.255. 255.255 can be seen as the layer 3 address which help to address the exact same hosts because it enables the broadcast address of the zero network which is the local network due to the fact that the IP broadcasts are often used by BOOTP and DHCP clients to find and send requests to their respective servers in which a message sent to a broadcast address may be received by all network-attached hosts.

Therefore the Layer 2 and Layer 3 destination addresses which the message contain are FF-FF-FF-FF-FF-FF and 255.255.255.255

7 0
3 years ago
A group of N stations share a 56-kbps pure ALOHA channel. Each station outputs a 1000-bit frame on average once every 100 sec, e
Sunny_sXe [5.5K]

Explanation:

Here, in the given statement, maximum flow capacity of the ALOHA channel = 18.4% = 0.184

Then, the stations N share 56 kbps

And, the channel rate = 0.184*56 = 10.304 kbps.  

Then, the outputs of the wach stations is 1000-bit frames/100 sec

\therefore, the output of the bits/ sec by each stations = \frac{1000}{100} bits/sec = 10 bits/sec

So, The output of the N stations is 10 bits/sec on the channel that having 10.304kb/sec

Finally, N = \frac{(10.304 \times 10^{3})}{10} = 1030 stations

3 0
3 years ago
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