mark must leave it for 5.5 months or 5 and half moths to gain 5600 in interest .
<u>Step-by-step explanation:</u>
Here we have , mark invests 8000 in an account that pays 12% interest and 2000 in one that pays 8%. if he leaves the money in the accounts for the same length of time, We need to find how long must he leave it to gain 5600 in interest . Let's find out:
Let mark invests 8000 in an account that pays 12% interest and 2000 in one that pays 8% for time x months , So total interest gain is 5600 i.e.
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
Therefore , mark must leave it for 5.5 months or 5 and half moths to gain 5600 in interest .
Answer:
I play fort nite i never like rocket
St
Answer:
B
Step-by-step explanation:
Becuase 1 divide 1/2
You make the division sign a multiplication sign
1 time 1/2
get the recipricol of 1/2 wich is 2
1 times 2/1
is 2
Answer:
"subtracting b, then dividing by m"
Step-by-step explanation:
To solve for a particular variable, look a the operations that are being performed on that variable. Then "undo" those operations in reverse order.
Here, the operations done to x are ...
• multiply by m
• add b to the product
Using the above recipe, first we "undo" the additon of b. We accomplish that by subtracting b from both sides of the equation. This gives ...
y - b = mx + b - b
y - b = mx . . . . . . . . . simplify
Next, we "undo" the multiplicatin by m. We accomplish that by dividing both sides of the equation by m.
(y -b)/m = mx/m
(y -b)/m = x . . . . . . . . simplify
This is your solution for x:
x = (y - b)/m
We found it by subtracting b, then dividing by m on both sides of the equation.
Multiply the equation:

The solution set is the same, because multiplying both sides of an equation by a non-zero number doesn't change the solution set. In fact, if you rewrite the equation as

Multiplying this by 3 (or whatever number, for all it matters) gives

Now, a product is zero if and only if at least one of the factor is zero. So, either
or 
Since the first is clearly impossible, the second one must be true, which is the original equation.