area = width * length
or
A = W * L
55 = W * (W+6)
solve for width:
0 = W^2 + 6W - 55
this is a quadratic and has two solutions -11 and 5
a length can only be non-negative so discard -11.
width W = 5 miles
now the length is 5+6 = 11 miles
Because

and

are inversely proportional, there is some constant

such that

Given that

and

, we have

So when

, you have
Answer:
Let A1 be original area
A2 dilated Area
A1=pi*d^2/4
=3.143*5^2/4
A1=19.63 unit square
A2= 3.143*15/4
A2=176.74 unit square
A2 is 9 times greater than A1
Hence the answer is B
Step-by-step explanation:
Would it be distribution were you multiply the three in? -3(b-7) -3*b and -3*-7 where your answer would be -3b+21
Answer:
Other number is 23
Step-by-step explanation:
Let the two numbers be x and y.
We have given that average of x and y is 17.
i.e 
if one of the number is 11,
Then , 
or (11 + y)/2 = 17
or 11 + y = 34
or y = 34 - 11
or y = 23