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3 years ago

15

Eli made 2 peanut butter and jelly sandwiches and cut each one into fourths. How many 1/4 sandwich pieces did Eli have?

1 answer:

max2010maxim [7]3 years ago

6 0

If Eli cut both pieces into 4th's, in all they would have 8 4th's.

Because 4 + 4 + 8 :)

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A sea lion jumped out of the water to a height of 3 feet above sea level. The number line shows the location of the sea lion at

Gelneren [198K]

Answer:

on the number line it would go from 0 and with a positive line go to 3 and when it’s dive down it would with a negative line go 9 spaces towards the negative side of the number line and the answer would be -6 I think tha

Step-by-step explanation:

3 0

3 years ago

Find the taylor series for f(x) centered at the given value of a. [assume that f has a power series expansion. do not show that

Bond [772]

Taylor series is $f(x) = ln2 + \sum_{n=1)^{\infty}(-1)^{n-1} \frac{(n-1)!}{n!(9)^{n}(x9)^{2} }$

To find the Taylor series for f(x) = ln(x) centering at 9, we need to observe the pattern for the first four derivatives of f(x). From there, we can create a general equation for f(n). Starting with f(x), we have

f(x) = ln(x)

$f^{1}(x)= \frac{1}{x} \\f^{2}(x)= -\frac{1}{x^{2} }\\f^{3}(x)= -\frac{2}{x^{3} }\\f^{4}(x)= \frac{-6}{x^{4} }$

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Since we need to have it centered at 9, we must take the value of f(9), and so on.

f(9) = ln(9)

$f^{1}(9)= \frac{1}{9} \\f^{2}(9)= -\frac{1}{9^{2} }\\f^{3}(x)= -\frac{1(2)}{9^{3} }\\f^{4}(x)= \frac{-1(2)(3)}{9^{4} }$

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Following the pattern, we can see that for $f^{n}(x)$ ,

$f^{n}(x)=(-1)^{n-1}\frac{1.2.3.4.5...........(n-1)}{9^{n} } \\f^{n}(x)=(-1)^{n-1}\frac{(n-1)!}{9^{n}}$

This applies for n ≥ 1, Expressing f(x) in summation, we have

$\sum_{n=0}^{\infinite} \frac{f^{n}(9) }{n!} (x-9)^{2}$

Combining ln2 with the rest of series, we have

$f(x) = ln2 + \sum_{n=1)^{\infty}(-1)^{n-1} \frac{(n-1)!}{n!(9)^{n}(x9)^{2} }$

Taylor series is $f(x) = ln2 + \sum_{n=1)^{\infty}(-1)^{n-1} \frac{(n-1)!}{n!(9)^{n}(x9)^{2} }$

Find out more information about taylor series here

brainly.com/question/13057266

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3 0

2 years ago

Joel can run around a 14– mi track in 81 sec, and Jason can run around the track in 69 sec. If the runners start at the same poi

Alenkasestr [34]

Answer:37.2 sec

Step-by-step explanation:

Given

Joel takes 81 sec for 14 mile long track

speed of joel $\frac{14}{1.35}$ mi/min=10.37 mi/min

Jason takes 69 sec for 14 mi track

so jason speed is $\frac{14}{1.15} mi/min=12.17 mi/min$

if both starts from same spot in opposite direction then

$\frac{x}{10.37}=\frac{14-x}{12.17}$

where x is distance covered by Joel

then x=6.44 miles

therefore time required

$t=\frac{6.44}{10.37}=0.621 min\approx 37.2 sec$

8 0

4 years ago

I need help finding m<1 please :)

Inessa [10]

Answer

c,116°

Step-by-step explanation:

i don't know how to draw a diagram?

Join ends of chord with the center making angles ∠2,∠3 and angle at the center.

angle at the center=128°

∠1=∠2+90°

∠2=∠3

∠2+∠3+128=180

∠2+∠2+128=180

2∠2=180-128=52

∠2=52/2=26

∠1=26+90=116°

sorry i can't explain properly without picure.

5 0

3 years ago

How many meters are in a exameter?

xz_007 [3.2K]

Answer:

1E18 OR 10^18

Step-by-step explanation:

The formula is multiply the length by 1e+18

8 0

3 years ago