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frutty [35]
2 years ago
7

What is the slope of the graphed function?

Mathematics
1 answer:
Aleonysh [2.5K]2 years ago
4 0
The slope is -1  as picking any two points, and finding (y2-y1)/(x2-x1)=-1
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Please help last question <br> 100 divided by 10 is what
s344n2d4d5 [400]

Answer:

10

Step-by-step explanation:

7 0
2 years ago
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Please help lol
natka813 [3]

Answer:

the opposite of a positive number is always negative

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2 years ago
12)If p and p' are the length of the perpendiculars drawn from the points (+-root a2-b2,0) to the line x/a cosA + y/b sinA = 1,
Elden [556K]

Answer:

Kindly refer to below explanation.

Step-by-step explanation:

Given equation of line:

\dfrac{x}{a}cos\theta+ \dfrac{y}{b}sin\theta =1\\OR\\\dfrac{x}{a}cos\theta+ \dfrac{y}{b}sin\theta-1=0

Given points are:

(\sqrt{a^2-b^2},0), (-\sqrt{a^2-b^2},0)

Formula for distance between a point and a line is:

If the point is (m, n) and equation of line is Ax+By+C = 0

Then, perpendicular distance between line and points is:

Distance = \dfrac{|Am+Bn+C|}{\sqrt{A^2+B^2}}

Here,

A = \dfrac{x}{a}cos\theta\\B = \dfrac{y}{b}sin\theta\\C = -1

For the first point:

m = \sqrt{a^2-b^2}, n = 0

By the above formula:

p and p' can be calculated as:

p\times p' =\\\Rightarrow  \dfrac{|\dfrac{cos\theta}{a}\times \sqrt{a^2-b^2}+ 0 -1|}{\sqrt{\dfrac{cos^2\theta}{a^2}+\dfrac{sin^2\theta}{b^2}}}\times \dfrac{|-\dfrac{cos\theta}{a}\times \sqrt{a^2-b^2}+ 0 -1|}{\sqrt{\dfrac{cos^2\theta}{a^2}+\dfrac{sin^2\theta}{b^2}}}\\\Rightarrow \dfrac{1-(\sqrt{a^2-b^2}\times \frac{cos\theta}{a})^2}{\dfrac{cos^2\theta}{a^2}+\dfrac{sin^2\theta}{b^2}}}

Formula used:

(x+y)(x-y) = x^2 - y^2

\Rightarrow \dfrac{\dfrac{a^2-a^2cos^2\theta+b^2cos^2\theta}{a^2}}{\dfrac{b^2cos^2\theta+a^2sin^2\theta}{a^2b^2}}\\\Rightarrow b^2(\dfrac{a^2sin^2\theta+b^2cos^2\theta}{a^2sin^2\theta+b^2cos^2\theta})\\\Rightarrow b^2

(Using the identity:

sin^2\theta +cos^2\theta = 1)

(Hence provded)

5 0
2 years ago
What expressions are equivalent to 4/12
ivann1987 [24]

Answer:

0.33 or 1/3 should be right

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3 years ago
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(A) they are complementary<br><br><br> (B) they are supplementary<br><br><br> (C) they are neither
jasenka [17]
b, they are supplementary angles, because the sum of the angles is 180 degrees
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